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Brilliant_brown [7]
4 years ago
5

Rewrite the following numbers in scientific notation.

Chemistry
1 answer:
oksian1 [2.3K]4 years ago
8 0
1.b
2.g
3.e
4.f
5.h
6.d
7.c
8.a
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Temka [501]

Answer:

Explanation:5,2 methyle- dhexene

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a classmate examines a substance that conducts electricity and is shiny but has no color. He says that is must be silver. What i
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He is making a conclusion from a single observation.

Silver isn’t the only metal that is shiny and has no colour.

For example, lithium, sodium, magnesium, and aluminium all have about the same colour as silver.

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Can you help me do this
Vlad1618 [11]

Answer:

24.4 amu

Explanation:

1. Multiply the mass numbers by their percentages using the rules of significant figures:

           Isotope 1: 24(.786) = 18.864 ⇒ 18.9

           Isotope 2: 25(.101) = 2.525 ⇒ 2.53

           Isotope 3: 26(.113) = 2.938 ⇒ 2.94

2. Find the sum of the products calculated using the rules of significant figures:

           18.9 + 2.53 + 2.94 = 24.37 ⇒ 24.4

5 0
3 years ago
A serving of Frosted Flakes cereal contains 235,000 J of energy. Calculate the change in temperature (ΔT) that would occur if th
allsm [11]
E = m x c x change in temp (delta T)
Change in temp = E / (m x c)
= 235000 / 1000* 4.18
= 235000 / 4180
=56.2200957

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6 0
3 years ago
Suppose that 25.0 mL of 0.10 M CH3COOH (aq) is titrated with 0.10 M NaOH (aq). What is the pH after the addition of 10.0 mL of 0
olya-2409 [2.1K]

Answer:

pH=-1.37

Explanation:

We are given that 25 mL of 0.10 M CH_3COOH is titrated with 0.10 M NaOH(aq).

We have to find the pH of solution

Volume of CH_3COOH=25mL=0.025 L

Volume of NaoH=0.01 L

Volume of solution =25 +10=35 mL=\frac{35}{1000}=0.035 L

Because 1 L=1000 mL

Molarity of NaOH=Concentration OH-=0.10M

Concentration of H+= Molarity of CH_3COOH=0.10 M

Number of moles of H+=Molarity multiply by volume of given acid

Number of moles of H+=0.10\times 0.025=0.0025 moles

Number of moles of OH^-=0.10\times 0.01=0.001mole

Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles

Concentration of H+=\frac{0.0015}{0.035}=4.28\times 10^{-2} m/L

pH=-log [H+]=-log [4.28\times 10^{-2}]=-log4.28+2 log 10=-0.631+2

pH=-1.37

6 0
3 years ago
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