The crystal structure of barium fluoride BaF₂ and magnesium fluoride MgF₂ is cubic and tetragonal lattice respectively.
There are difference between the cubic and tetragonal lattice of any crystal. For cubic lattice a = b = c and α = β = γ = 90⁰ and for tetragonal lattice a = b ≠ c and α = β = γ = 90⁰ (where a, b and c are the edge length of the lattice and α, β, γ angle of the crystal lattice).
The difference of the structure depends on the size of the ions present in the compound. In BaF₂, the ions are Ba²⁺ and F⁻. In MgF₂, the ions are Mg²⁺ and F⁻.
Although the size of the anion in both the crystal is same, there is a huge difference between the size of the cation, which affect the crystal lattice of the compound.
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Answer:
0.082 M
Explanation:
First we calculate the moles of KOH added, by multiplying its volume and concentration:
- 0.22 M * 16 mL = 3.52 mmol KOH
Given that <em>one mole of acid reacts with one mole of base</em>, in the lactic acid sample there were 3.52 acid moles as well.
Finally we divide the acid moles by the volume, to calculate the concentration:
- 3.52 acid moles / 43 mL = 0.082 M