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mina [271]
3 years ago
13

What is the formula for Impedance for circuit with R, C, and L?

Physics
1 answer:
NikAS [45]3 years ago
3 0

Answer:

 The formula for Impedance for circuit with R, C, and L are:

    z=\sqrt{R^{2}+\left ( \omega L-\frac{1}{\omega C} \right )^2}

The impedance Z of the series RLC circuit depend upon angular frequency ω. Impedance is measured in ohms and resistance (R), inductance reactance and capacitive reactance. Series RLC circuit consist of the resistance, a capacitance and an inductance connected in the circuits. Electrical impedance is the measurement of the opposition that a circuit present in a current.

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When there is faster-moving water between two ships, are the ships sucked together or pushed together? explain?
Zigmanuir [339]
The ships should get suck together as the water must be replaced from the sides.  Please mark Brainliest!!!
7 0
3 years ago
20.0 moles, 1840 g, of a nonvolatile solute, C 3H 8O 3 is added to a flask with an unknown amount of water and stirred. The solu
Anastasy [175]

Answer:

0.144 kg of water

Explanation:

From Raoult's law,

Mole fraction of solvent = vapor pressure of solution ÷ vapor pressure of solvent = 423 mmHg ÷ 528.8 mmHg = 0.8

Let the moles of solvent (water) be y

Moles of solute (C3H8O3) = 2 mole

Total moles of solution = moles of solvent + moles of solute = (y + 2) mol

Mole fraction of solvent = moles of solvent/total moles of solution

0.8 = y/(y + 2)

y = 0.8(y + 2)

y = 0.8y + 1.6

y - 0.8y = 1.6

0.2y = 1.6

y = 1.6/0.2 = 8

Moles of solvent (water) = 8 mol

Mass of water = moles of water × MW = 8 mol × 18 g/mol = 144 g = 144/1000 = 0.144 kg

7 0
3 years ago
Calculate the mass of an ice block of volume 12m³. the density of the ice is 920kg/m³.​
beks73 [17]

Mass = density • volume

so (12)(920)(kg/m^3•m^3)

11040 kg

4 0
3 years ago
What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the cur
k0ka [10]

Answer:

Incomplete question

This is the completed question

If the resistor in the circuit had a larger resistance then the current would be then have to be proportionally smaller. Because the batteries each give off 1.5 volts then the current would have to be the variable that would change. What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the current? What would happen to the resistor?

Explanation:

Using ohms law as our basis

Ohms law state that, the voltage in an ohmic conductor is directly proportional to the current

V∝I

Resistance is the constant of proportionality

Then

V=iR

Since we want a relationship between current and resistance.

then, I=V/R

So, current is inversely proportional to Resistance

as the current increase the resistance reduce and as the current reduces the resistance increases.

a. So, increasing the voltage from 1.5V to 12V increases the current In the circuit because voltage Is directly proportional to I.

From ohms law

V=iR

When v =1.5V

I=1.5/R

When V increase to 12V

I=12/R

I.e, it increases by a factor of 8. Eight times it's initial value

b. Now, the resistance in the circuit is the constant of proportionality and it doesn't change in a given circuit expect when using a variable resistoa r like rheostat.

6 0
3 years ago
A 12.0 kg rock slides off the edge of a bridge and falls into the water 25.0 meters below. what is the kinetic energy of the roc
Pavel [41]
During the fall, all the initial potential energy of the rock 
U=mgh
has converted into kinetic energy of motion
K= \frac{1}{2}mv^2
where h is the initial height of the rock, m its mass, and v its velocity just before hitting the water. So, for energy conservation, we have
U=K
and so we can find the value of K, the kinetic energy of the rock just before hitting the ground:
K=U=mgh = (12.0 kg)(9.81 m/s^2)(25.0 m)=2943 J
7 0
3 years ago
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