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Alex777 [14]
3 years ago
8

Naomi has a very high deductible and an HSA. Naomi most likely has a ______.

Health
2 answers:
vovangra [49]3 years ago
5 0
Naomi has a very high deductible and an HSA. Naomi most likely has a low premium
Lelu [443]3 years ago
5 0

Answer:

I believe the answer is C - tax-free savings account.

Explanation:

HSA in medical terms stands for Health Savings Account, so C would make the most sense. I am not entirely sure, so correct me if I'm wrong but ?? hope this helps.

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An effective way to advocate for a cause is to talk to a person in power that can help you make a positive change.
Rom4ik [11]

Answer: true

Explanation: this can help the reach of your project

6 0
3 years ago
A young woman, age 22, has been suffering with clinical depression. She has an older brother who is exceptionally bright and hig
stealth61 [152]

Answer:

The family can show their affection towards her and show her that they do care for her and that they don't want her to harm herself. They can explain to her that she will never be alone and they can also come to therapy and show that they will help too.

Explanation:

6 0
3 years ago
Which of the following describes internal coping strategies
Naily [24]
What are the answer choices

3 0
3 years ago
If 2^x=3^y=12^z, show that 1÷z=1÷y+2÷x.....​
Ostrovityanka [42]

Answer:

Proof of \dfrac{1}{z}}=\dfrac{1}{y}+\dfrac{2}{x}  is shown below.

Explanation:

The given equation is

2^x=3^y=12^z

To prove : \dfrac{1}{z}=\dfrac{1}{y}+\dfrac{2}{x}

Proof : Let as assume,

2^x=3^y=12^z=k

2^x=k\Rightarrow 2=k^{\frac{1}{x}}    ...(1)

3^y=k\Rightarrow 3=k^{\frac{1}{y}}      ...(2)

12^z=k\Rightarrow 12=k^{\frac{1}{z}}    ...(3)

We know that

12=2\times 2\times 3

12=(2)^2\times 3

Using (1), (2) and (3), we get

k^{\frac{1}{z}}=(k^{\frac{1}{x}})^2\times k^{\frac{1}{y}}

k^{\frac{1}{z}}=k^{\frac{2}{x}}\times k^{\frac{1}{y}}

k^{\frac{1}{z}}=k^{\frac{2}{x}+\frac{1}{y}}

On comparing both sides, we get

\dfrac{1}{z}}=\dfrac{2}{x}+\dfrac{1}{y}

\dfrac{1}{z}}=\dfrac{1}{y}+\dfrac{2}{x}

Hence proved.

8 0
3 years ago
Before exercising you should allow your pulse rate to increase gradually by
Nutka1998 [239]
I should assume it warming up. You warm up before you play any sport right? Playing sports is exercising.

Hope this helps you!!
4 0
3 years ago
Read 2 more answers
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