Answer:
In SI units, its value is approximately 6.674×10−11 m3⋅kg−1⋅s−2. The modern notation of Newton's law involving G was introduced in the 1890s by C. V. Boys. The first implicit measurement with an accuracy within about 1% is attributed to Henry Cavendish in a 1798 experiment.
Explanation:
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Assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
Missing part of the question: determine the magnitude of Porsha's acceleration.
Given the data in the question;
- Mass of Porsha;
![m_{porsha} = 60kg](https://tex.z-dn.net/?f=m_%7Bporsha%7D%20%3D%2060kg)
- Mass of Zorn;
![m_{zorn} = 40kg](https://tex.z-dn.net/?f=m_%7Bzorn%7D%20%3D%2040kg)
- Force of Porsha push;
![F_{porsha} = 168N](https://tex.z-dn.net/?f=F_%7Bporsha%7D%20%3D%20168N)
Magnitude of Porsha's acceleration; ![a = \ ?](https://tex.z-dn.net/?f=a%20%3D%20%5C%20%3F)
To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:
![F = m*a](https://tex.z-dn.net/?f=F%20%3D%20m%2Aa)
Where m is the mass of the object and a is the acceleration.
We substitute the mass of Porsha and the force he used into the equation
Therefore, assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
Learn more: brainly.com/question/25125444
<span>If the Earth rotated more slowly about its axis, your apparent weight would
A) increase.
B) decrease.
C) stay the same.
D) be zero.
</span>A) increase.
Answer: 11,100 ft/s^2
1) Constant acceleration=> uniformly accelerated motion.
2) Formula for uniformly accelerated motion:
Vf = Vo + at
3) Data:
Vo = 1,100 ft/s
a = 1,000 ft/s^2
t = 10.0 s
4) Solution:
Vf = 1,100 ft/s + 1,000 ft/s^2 * 10.0 s = 1,100 ft/s + 10,000 ft/s
Vf = 11,100 ft/s