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Sever21 [200]
3 years ago
5

If a/3 = b/2 , what are the following ratios?

Mathematics
1 answer:
sergejj [24]3 years ago
6 0

Answer:

a/3 = b/2

a/b = 2/3

I guess you wanna know a:b

So it's 2:3

You might be interested in
How much money will you have if you started with $1250 and put it in an account that earned 6.7% every year for 14 years?
KatRina [158]

Answer:

$3098.93

Step-by-step explanation:

We can use the formula for compound growth to solve this. The formula is:

F=P(1+r)^t

Where

F is the future value (the value at end of 14 years, our answer)

P is the initial amount invested ($1250)

r is the interest rate, in decimal (6.7% is 0.067)

t is the time in years (14, in our case)

<em>Plugging in all the information</em> we have:

F=P(1+r)^t\\F=1250(1+0.067)^14\\F=1250(1.067)^14\\F=3098.93

The account will accrue $3098.93 after 14 years.

3 0
3 years ago
IN A CLASS OF 30 STUDENTS 13 OF THEM ARE BOYS WHAT PERCENTAGE ARE GIRLS?
mestny [16]
Class of students - number of students that are boys = numbers of students that are girls

30 - 13 = 17

To change the number of students that are girls into percentage...

17/1 * 1/100 = 17/100

17/100 in a % form = 17%

The percentage of girls in the class is 17%

5 0
3 years ago
Stan's back account balance is less than -20.00 dollars but greater than -21.00. what could stan's account balance be?
neonofarm [45]
It could be -20.50 but not sure do u have answer choices
7 0
3 years ago
When comparing the shapes of the two sets of data, what conclusion can someone draw?
ch4aika [34]

Answer:D)The girls a re generally taller than the boys

Step-by-step explanation:

4 0
3 years ago
You will need the same dataset used for problem 3 in homework 1 (the dataset obtained from the yahoo website with the company yo
stepladder [879]

Answer:

a) The probability of sampling at random a fish that is smaller in size than the value you would obtain by subtracting half the standard deviation from the average is 0.3085.

b) The probability of sampling at random a fish that is greater in size than the value you would obtain by adding half the standard deviation from the average is 0.3085.

c) The probability of sampling at random a fish that has a size between the two values is 0.383.

d) The 25th and 75 percentiles of fish size for the population using the normal distribution table is 5.69 and 5.87 respectively.

e) The probability that the average calculated will be less than the value is 0.3707.

Step-by-step explanation:

For the given data set mean (\mu) = 5.75913

Standard deviation (\sigma) = 0.172229

Variance (\sigma2) = 0.0296

Here we get is

a)

P(x < \mu - \sigma/2) = p(x < 5.673) \\\\          = 0.3085

b)

P(x < \mu + \sigma/2) = p(x < 5.845) \\\\= 0.3085

c)

P(\mu - \sigma/2 < x < \mu + \sigma/2) = p(5.673 < x < 5.845) \\\\= 0.383

d)

25th percentile:-

= 25*[(n+1)/100]th term \\\\= 5.69

75the percentile:-

= 75*[(n+1)/100]th term\\\\ = 5.87

e)  

p(x < \mu - \sigma/3) = p(x < 5.7017) \\\\= 0.3707

7 0
3 years ago
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