Answer:
The dataset image is attached.
The question has three parts:
a) Find the frequency distribution and relative frequency distribution for these data.
b) Construct a percentage bar chart for these data
c) Construct a percentage pie chart for these data
Explanation:
a)
Frequency distribution tell us how often something occurs.
Frequency distribution
Experience Rating Frequency
OutStanding 14
Very Good 10
Good 5
Average 1
Poor 0
This relative frequency distribution table shows how something are distributed.
Relative Frequency Distribution
Experience Rating Frequency Relative Frequency
OutStanding 14 14/30 = 7/15 = 0.467
Very Good 10 10/30 = 1/3 = 0.333
Good 5 5/30 = 1/6 = 0.167
Average 1 1/30 = 0.033
Poor 0 0
Total 30 1.000
b) Chart image is attached
c) Chart image is attached
Answer:
Explanation:
From the given information:
Water freezing temp.
Heat rejected temp
Recall that:
The coefficient of performance is:
Again:
The efficiency given by COP can be represented by:
Finally; the power input in an hour can be determined by using the formula:
In hp; since 1 kW = 1.34102 hp
6.86kW will be = (6.86 × 1.34102) hp
= 9.199 hp
Answer:
hello below is missing piece of the complete question
minimum size = 0.3 cm
answer : 0.247 N/mm2
Explanation:
Given data :
section span : 10.9 and 13.4 cm
minimum load applied evenly to the top of span : 13 N
maximum load for each member ; 4.5 N
lets take each member to be 4.2 cm
Determine the max value of P before truss fails
Taking average value of section span ≈ 12 cm
Given minimum load distributed evenly on top of section span = 13 N
we will calculate the value of by applying this formula
= = 1.56 * 10^-5
next we will consider section ; 4.2 cm * 0.3 cm
hence Z (section modulus ) = BD^2 / 6
= ( 0.042 * 0.003^2 ) / 6 = 6.3*10^-8
Finally the max value of P( stress ) before the truss fails
= M/Z = ( 1.56 * 10^-5 ) / ( 6.3*10^-8 )
= 0.247 N/mm2