Aesthetic elements are the components that are added to the design to be considered pleasing to the eye.
<h3>What are aesthetic elements?</h3>
They are those characteristics of an object that deal with the outward appearance or beauty of an object, that is, they are those elements that make it valuable, appreciable, relevant or transcendent.
To do this, the qualities must be in the design of the object but must also be perceived by the consumer, the aesthetic being what we like to perceive in objects.
Therefore, we can conclude that aesthetic elements are the components that are added to the design to be considered pleasing to the eye.
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This is a very very difficult one for me, let me get back to you with the proper answer.
Answer: ε₁+ε₂+ε₃ = 0
Explanation: Considering the initial and final volume to be constant which gives rise to the relation:-
l₀l₀l₀=l₁l₂l₃

taking natural log on both sides

Considering the logarithmic Laws of division and multiplication :
ln(AB) = ln(A)+ln(B)
ln(A/B) = ln(A)-ln(B)

Use the image attached to see the definition of true strain defined as
ln(l1/1o)= ε₁
which then proves that ε₁+ε₂+ε₃ = 0
Answer:
14.506°C
Explanation:
Given data :
flow rate of water been cooled = 0.011 m^3/s
inlet temp = 30°C + 273 = 303 k
cooling medium temperature = 6°C + 273 = 279 k
flow rate of cooling medium = 0.02 m^3/s
Determine the outlet temperature
we can determine the outlet temperature by applying the relation below
Heat gained by cooling medium = Heat lost by water
= ( Mcp ( To - 6 ) = Mcp ( 30 - To )
since the properties of water and the cooling medium ( water ) is the same
= 0.02 ( To - 6 ) = 0.011 ( 30 - To )
= 1.82 ( To - 6 ) = 30 - To
hence To ( outlet temperature ) = 14.506°C