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ASHA 777 [7]
2 years ago
11

Can someone please help me with this. Thank you. Ill mark you as brainly.

Engineering
1 answer:
Contact [7]2 years ago
4 0

Answer:

5, 6, 4, 3, 2, 1

Explanation:

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A metallic material with yield stress of 140 MPa and cross section of 300 mm x 100 mm, is subjected to a tensile force of 8.00 M
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Answer:Yes,266.66 MPa

Explanation:

Given

Yield stress of material =140 MPa

Cross-section of 300\times 100 mm^2

Force(F)=8 MN

Therefore stress due to this Force(\sigma)

\sigma =\frac{F}{A}=\frac{8\times 10^6}{300\times 100\times 10^{-6}}

\sigma =266.66 \times 10^{6} Pa

\sigma =266.66 MPa

Since induced stress  is greater than Yield stress therefore Plastic deformation occurs

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