Answer: um wuh anyways thxs for the points!
Explanation: ....:/
Answer:
the mean time I was wondering if you have any questions or need any further information please contact me at the mean time I was
Answer:
a. the base must be more positive than the emitter
Explanation:
A transistor can be defined as a semiconductor component that is used to control the flow of voltage or current and as a gate (switch) for electronic signals. Thus, a transistor allows for the amplification, control and generation of electronic signals in a circuit. The three (3) basic parts of a transistor are; base, emitter and collector.
Basically, there are two (2) main types of transistor and these are;
1. PNP transistor.
2. NPN transistor.
Biasing of a transistor can be defined as the process of providing the controlled amount of direct current (DC) voltage or current conditions so as to enable the transistor amplify the alternating current (AC) input signal correctly.
Hence, to forward bias an NPN transistor, the base must be more positive than the emitter because the majority carriers are electrons which are moved from the n-type region to the p-type region while the minority carriers are holes.
This ultimately implies that, for an NPN transistor to conduct current in milliamps, its base-emitter junction must be forward biased.
Answer:
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Explanation:
if that is what your meaning
Answer:
0.0432 m^3/s
Explanation:
Internal diameter of smaller pipes = 2.5 cm = 0.025 m
pipa wall thickness = 3 mm = 0.003 m
internal diameter of larger pipes = 8 cm = 0.8 m
velocity of region between smaller and larger pipe = 10 m/s
Calculate discharge in m^3/s
First we calculate the area of the smaller pipe
A =
=
= 0.00023571 m^2
next we calculate area of fluid between the smaller pipes and larger pipe
A = ![[\frac{\pi }{4} D^{2} _{L} ] - 3(A_{s})](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20D%5E%7B2%7D%20_%7BL%7D%20%20%5D%20-%203%28A_%7Bs%7D%29)
= ![[ \frac{\pi }{4} (0.08 )^2 - 3 ( 0.00023571 )]](https://tex.z-dn.net/?f=%5B%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%280.08%20%29%5E2%20-%203%20%28%200.00023571%20%29%5D)
= [ 0.00502857 - 0.00070713 ]
= 0.00432144 m^2
hence the discharge in m^3/s
Q = AV
= 0.00432144 * 10
= 0.0432 m^3/s