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kherson [118]
2 years ago
5

Answer the following questions, and very briefly explain your answer:

Engineering
1 answer:
alexandr1967 [171]2 years ago
5 0

Answer:

A) micro defects are left behind on the surface of metal components during the manufacturing process. These defects, in the form of micro-cracks or pits, becomes initiation sites for crack propagation or corrosion. Removing these imperfections on the surface of metal parts by electroplating greatly improves the life of metal components.

B) it will reduce fatigue crack growth.

Dispersion hardening involves the inclusion of small, hard particles in the metal, thus restricting the movement of dislocations, and thereby raising the strength properties. In dispersion hardening it is assumed that the precipitates do not deform with the matrix and that a moving dislocation bypasses the obstacles (precipitates) by moving in the clean pieces of crystal between the precipitated particles.

C) stress concentrations such as changes in section with sharp corners caused yielding, which will typically occur first at a stress concentration. For ductile materials localised plastic deformation can cause a redistribution of stress, enabling the component to continue to carry load. Brittle materials will typically fail at the stress concentration. Repeated loading may cause a fatigue crack to initiate and slowly grow at a stress concentration leading to the failure of even ductile materials. Fatigue cracks always start at stress raisers, so removing such defects increases the fatigue strength.

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1. A copper block of volume 1 L is heat treated at 500ºC and now cooled in a 200-L oil bath initially at 20◦C. Assuming no heat
MaRussiya [10]

Answer:

final temperature T = 24.84ºC

Explanation:

given data

copper volume = 1 L

temperature t1 = 500ºC

oil volume = 200 L

temperature t2 = 20ºC

solution

Density of copper \rho cu = 8940 Kg/m³

Density of light oil  \rho oil = 889 Kg/m³

Specific heat capacity of copper Cv = 0.384  KJ/Kg.K

Specific heat capacity of light oil Cv = 1.880 KJ/kg.K

so fist we get here mass of oil and copper that is

mass = density × volume   ................1

mass of copper = 8940 × 1 ×  10^{-3}  = 8.94 kg  

mass of oil = 889 × 200 × 10^{-3}  =  177.8 kg  

so we apply here now energy balance equation that is

M(cu)\times Cv \times (T-T1)_{cu} + M(oil) \times Cv\times (T-T2)_{oil}  = 0

put here value and we get T2

8.94\times 0.384 \times (T-500) + 177.8 \times 1.890\times (T-20)  = 0

solve it we get

T = 24.84ºC

7 0
2 years ago
What is a core self-evaluation, include identifying and explaining the components of core self-evaluation. And, how a group lead
Brilliant_brown [7]

Answer and Explanation:

Core self-evaluations (CSEs) stands for a wide personality trait that comprises of 4 positive individual traits, namely:

(1) self-efficacy

(2) self esteem

(3) locus of control

(4) emotional stability.

Baiscally, when people have a positive evaluation about themselves, or quality core self-evaluation, they believe that they are worthy and fit for a task. They trust their capability and effectiveness. This leads to some implications in their managers duties and careers, which could either be positive or negative.

A group leader can use CSEs to create a more effective unit by implementing the ten items points of Generalized Self Efficacy Tool to test the self efficiency of individual personnels in that unit.

8 0
3 years ago
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san4es73 [151]
Builderman is dksbdkbsnsbs
5 0
2 years ago
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Match the scenario to the term it represents.
Ann [662]

Answer:

i nrfvewv

Explanation:

3 0
2 years ago
A DC generator turns at 2000 rpm and has an output of 200 V. The armature constant is 0.5 V-min/Wb, and the field constant of th
WITCHER [35]

Answer:

b. 10A

Explanation:

Using the formula, E= k × r×I

200= 0.5 ×2000×0.02×I

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Dividing with 20

I = 200/20= 10A

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3 years ago
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