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Katarina [22]
3 years ago
8

What is the ILS stand for

Engineering
2 answers:
Georgia [21]3 years ago
7 0

<em>ILS</em><em> </em><em>stands</em><em> </em><em>for</em><em> </em><em>Instrument</em><em> </em><em>Landing</em><em> </em><em>System</em><em>.</em>

<em>It is used to help provide lateral and vertical guidance to the pilots when landing an aircraft.</em>

Alika [10]3 years ago
6 0

Answer:

Instrument Landing System

Explanation:

The ILS works by sending radio waves from the runway to the aircraft. Which is then intercepted and is used to guide the aircraft onto the runway.

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How does a belt operated supercharger work? (Not a turbo charger)
icang [17]

Answer:

A root-type supercharger works similar to that of an air pump. It pumps air into the intake of the engine. Within the engine cylinder, the compression of the air-fuel mixture takes place. A centrifugal supercharger, works like a turbo, compresses the air in it and then delivers it to the engine.

3 0
3 years ago
Draw the free-body diagram of the beam which supports the 80-kg load and is supported by the
Sauron [17]

The free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

The first image shows the diagram of the beam and the second image shows the free-body diagram of the beam.

The resolution of forces in the system is well understood by the principle of equilibrium where a stationary body will remain balanced when subject to parallel forces provided that the total sum of the overall external forces is zero.

The free-body diagram is a graphical representation used to visualize the forces applied to an object.

The equilibrium of forces on the x-axis is:

\mathbf{\sum F_x  = 0}

The equilibrium of forces on the y-axis is:

\mathbf{\sum F_y = 0}

The equilibrium condition at any point is:

\mathbf{\sum M = 0}

From the free body diagram attached in the second image below,

  • the horizontal reaction is located at point A as \mathbf{ A_x}
  • the vertical reaction is  located at point A  as \mathbf{A_y}
  • the tension =  T
  • the weight = W

Therefore, we can conclude that the free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

Learn more about the free-body diagram here:

brainly.com/question/19345060?referrer=searchResults

5 0
2 years ago
Atmospheric pressure is measured to be 14.769 psia. a. What would be the equivalent reading of a water barometer (inches of H20)
Fofino [41]

Answer:

(a) water height =408.66 in.

(b) mercury height=30.04 in.

Explanation:

Given: P=14.769 psi     ( 1 psi= 6894.76 \frac{N}{m^2} )

we know that   P=\rho\times g\timesh

where \rho =Density,g=9.81\frac{m}{s^2}

     h=height.

Given that P=14.769 psi ⇒P= 101828.6 7\dfrac{N}{m^2}

(a) P=\rho_{w}\times g\times h_{w}  

     \rho_{w}=1000\frac{Kg}{m^3}

⇒101828.67=1000\times 9.81\times h_{w}

h_{w}=10.38 m

So water barometer will read 408.66 in.            (1 m=39.37 in)

(b)  P=\rho_{hg}\times g\times h_{hg}

     \rho_{hg}=13600

So 101828.67=13600\times 9.81\times h_{hg}

h_{hg}=0.763 m

So mercury barometer will read 30.04 in.

6 0
3 years ago
Two metallic terminals protrude from a device. The terminal on the left is the positive reference for a voltage called vx (the o
tresset_1 [31]

Answer:

Vx = 6.242 x 10raised to power 15

Vy = -6.242 x 10raised to power 15

Explanation:

from E = IVt

but V = IR from ohm's law and Q = It from faraday's first law

I = Q/t

E = Q/t x V x t = QV

hence, E =QV

V = E/Q

3 0
3 years ago
Read 2 more answers
A hollow pipe is submerged in a stream of water so that the length of the pipe is parallel to the velocity of the water. If the
Arlecino [84]

Answer:

increases by a factor of 6.

Explanation:

Let us assume that the initial cross sectional area of the pipe is A m² while the initial velocity of the water is V m/s², hence the flow rate of the water is:

Initial flow rate = area * velocity = A * V = AV m³/s

The water speed doubles (2V m/s) and the cross-sectional area of the pipe triples (3A m²), hence the volume flow rate becomes:

Final flow rate = 2V * 3A = 6AV m³/s = 6 * initial flow rate

Hence, the volume flow rate of the water passing through it increases by a factor of 6.

8 0
3 years ago
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