All categories

4 years ago

Plant scientists would not do which of the following?

Engineering

2 answers:

zavuch27 [327]4 years ago

6 0

Explanation:

i think option 4 is correct answer because itsrelated to animal not plants.

victus00 [196]4 years ago

5 0

I think 4 th option

You might be interested in

How do you extablish a chain of dimensions

kap26 [50]

Answer:

Certamente você conhece três dimensões: comprimento, largura e profundidade. Além disso, quando se pensa um pouco fora da caixa também seria possível adicionar a dimensão do tempo.

Provavelmente, algumas pessoas viajam na maionese quando toca-se nesse assunto. Vem em suas mentes universos paralelos e até mesmo realidades alternativas. Mas também não se trata disso.

Explanation:

Basicamente as dimensões são as facetas do que nós percebemos a ser realidade. Existem muitos debates sobre dimensões na física. Um dos que mais chamam a atenção se chama Teoria das Cordas.

5 0

3 years ago

A venturi meter is to be installed in a 63 mm bore section of a piping system to measure the flow rate of water in it. From spac

Alex Ar [27]

Answer:

Throat diameter $d_2$ =28.60 mm

Explanation:

Bore diameter $d_1=63mm$ ⇒ $A_1=3.09\times 10^{-3} m^2$

Manometric deflection x=235 mm

Flow rate Q=240 Lt/min⇒ Q=.004 $\frac{m^3}{s}$

Coefficient of discharge $C_d$ =0.8

We know that discharge through venturi meter

$Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}$

$h=x(\dfrac{S_m}{S_w}-1)$

$S_m$ =13.6 for Hg and $S_w$ =1 for water.

$h=0.235(\dfrac{13.6}{1}-1)$

h=2.961 m

Now by putting the all value in

$Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}$

$0.004=0.8\times \dfrac{3.09\times 10^{-3} A_2\sqrt{2\times 9.81\times 2.961}}{\sqrt{(3.09\times 10^{-3})^2-A_2^2}}$

$A_2=6.42\times 10^{-4} m^2$

⇒ $d_2$ =28.60 mm

So throat diameter $d_2$ =28.60 mm

4 0

3 years ago

How to make a police car

S_A_V [24]

search it and you will get on internet

3 0

2 years ago

If car 3 in the graph above continues to decelerate at 1.2 mph/s, how fast would it be going at t=20 s?

vladimir2022 [97]

Answer:

3sa

Explanation:

asdfasdfas

8 0

3 years ago

Which of the following Python lines calculates the standard deviation of variables Exam1 and Exam4 from a CSV file called ExamSc

Virty [35]

Answer:

The option B calculates the standard deviation of variables Exam1 and Exam4.

Explanation:

First, let's write the first two lines correctly:

import pandas as pd
scores = pd.read_csv('ExamScores.csv')

Now, let's analyse each option:

- The option A is incorrect

The expression std[['Exam1','Exam4']] is the incorrect part because in this case std is working as a variable and the std was not previously declared. So it will generate an error.

- The option C is incorrect

The expression std[['Exam1','Exam4']].scores() is incorrect because of two reasons: first, std is working as a variable and the std was not previously declared (as in option A), second, .scores() is working as a method and in this case, scores is the variable. So it will generate an error.

- The option D is incorrect

The expression [['Exam1']] is the incorrect part because it doesn't include the 'Exam4' and the problem is asking for the standard deviation of variables Exam1 and Exam4.

- The option B is CORRECT

The expression std[['Exam1','Exam4']] refers to the variables Exam1 and Exam4 from the total exams. As scores is a pandas variable and .std() is a method provided by pandas library, the expression .std() allows to get the deviation standard of the variables Exam1 and Exam4.

Thus, the option B calculates the standard deviation of variables Exam1 and Exam4.

4 0

3 years ago