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3 years ago

The _ the object, the _ effect a force will have on its motion.

Physics

1 answer:

UkoKoshka [18]3 years ago

3 0

The correct choice is D. But it's only correct if all the experiments are done on the same planet.

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How much work does the charge escalator do to move 2.30 μC of charge from the negative terminal to the positive terminal of a 3.

loris [4]

Answer:

$6.9\times 10^{-6} J$

Explanation:

We are given that

Charge=q= $2.3\mu C=2.3\times 10^{-6} C$

$1\mu C=10^{-6} C$

Potential difference=V=3 V

We know that

Work done= $V\times q$

Using the formula

Work done by charge to move from the negative terminal to the positive terminal of battery= $2.3\times 10^{-6}\times 3$ J

Work done by charge to move from the negative terminal to the positive terminal of battery= $6.9\times 10^{-6} J$

6 0

3 years ago

A rubber band has a spring constant of 75 N/m. How much force is required to stretch the rubber band 0.02 m past its natural len

ale4655 [162]

Answer:

(75 x 0.02) = 1.5 N

Explanation:

7 0

3 years ago

A force of 50 n acts on abody of mass 5 kg .calculate the acceleration produced

Leokris [45]

Answer:

a = 10 m/s²

Explanation:

Given:

Force = F = 50 N

Mass = m = 5 kg

Required:

Acceleration = a = ?

Formula:

F = ma

Solution:

Rearranging the formula for a

=> a = F/m

=> a = 50/5

=> a = 10 m/s²

8 0

3 years ago

Does the sun always shine directly overhead at the equator at noon

Nikitich [7]

The sun always shines directly overhead at noon. This is because the equator always gets the equivalent amount of sunlight. The area always get 12 hours of sunlight, because it's 0 degrees north and south and it's at the center of the Earth.

4 0

3 years ago

A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 4.79 g coins stacked over the 28.8 cm mark, th

masha68 [24]

To solve the exercise, the key concept to be addressed is the Mass Center.

The center of mass of an object is measured as,

$X_{cm} = \frac{\sum m_ix_i}{\sum m_i}$

$X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}$

Our values are given by,

$x_1 = 50cm$

$m_1 = ?$

$x_2 =28.8cm$

$m_2 = 4.79g$

$x_3 = 28.8cm$

$m_3 = 4.79g$

$X_{cm} = 38.4cm$

Replacing the values in our previous equation we have,

$X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}$

$38.4 = \frac{m_1(50)+2(28.8*4.79)}{m_1+2*4.79}$

$38.4(m_1+2*4.79)= m_1(50)+2(28.8*4.79)$

$38.4m_1 +367.872 = 50m_1+275.904$

$11.6m_1 = 91.968$

$m_1 = 7.928g$

Therefore the mass of the meter stick is 7.928g

7 0

3 years ago

The _______ the object, the _______ effect a force will have on its motion.

The _ the object, the _ effect a force will have on its motion.