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Allisa [31]
3 years ago
13

____ returns energy to the atmosphere?

Chemistry
1 answer:
mezya [45]3 years ago
5 0
The earth returns energy to the atmosphere.
You might be interested in
A 13.00 g sample of a compound contains 4.15 g potassium (k), 3.76 g chlorine (cl), and oxygen (o). calculate the empirical form
MrRissso [65]

To solve this problem, let us all convert the mass of each element into number of moles using the formula:

moles = mass / molar mass

Where,

molar mass K = 39.10 g / mol

<span>molar mass Cl = 35.45 g / mol</span>

molar mass O = 16 g / mol

<span>and mass O = 13 g – 4.15 g – 3.76 g  = 5.09 g</span>

 

moles K = 4.15 g / (39.10 g / mol) = 0.106 mol

<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>

moles O = 5.09 g / (16 g / mol) = 0.318 mol

 

The ratio becomes:

0.106 K: 0.106 Cl: 0.318 O

We divide all numbers with the smallest number, in this case 0.106. This becomes:

K: Cl: 3O

 

Therefore the empirical formula is:

KClO_{3}

7 0
3 years ago
A chemist determined by measurement that 0.0450 moles of iron participated in a chemical reaction. Calculate the mass of iron th
Rzqust [24]

Answer:

2.51 g

Explanation:

The mass of 1 mol of iron is 55.84 g.

For 0.0450 mol,

\text{Mass of Fe} = \text{0.0450 mol} \times \dfrac{\text{55.84 g Fe}}{\text{1 mol Fe}} = \textbf{2.51 g Fe}

5 0
3 years ago
Read 2 more answers
Percentage Yield
scoundrel [369]

Q.No. 1:

            You have 20.0 g of CaCO₃. You decompose it by heat, and weigh the calcium oxide that  remains. You have 10.3 grams. What is the % yield?

Answer:

               %age Yield = 92.37 %

Solution:

               The balance chemical equation for given decomposition reaction is;

                                           CaCO₃ → CaO + CO₂

Step 1: <u>Calculate Moles of CaCO₃:</u>

                Moles  =  Mass / M.Mass

                Moles  =  20.0 g / 100.08 g/mol

                Moles  =  0.199 moles of CaCO₃

Step 2: <u>Calculate theoretical amount of CaO produced;</u>

According to equation,

              1 moles of CaCO₃ produced  =  1 mole of CaO

So,

           0.199 moles of CaCO₃ will produce  =  X moles of CaO

Solving for X,

                     X  =  0.199 mol × 1 mol / 1 mol

                     X  =  0.199 mol of CaO

Also,

         Mass  =  Moles × M.Mass

         Mass  =  0.199 mol × 56.07 g/mol

         Mass  =  11.15 g of CaO

Step 3: <u>Calculate %age Yield as;</u>

         %age Yield  =  Actual Yield / Theoretical Yield × 100

         %age Yield  =  10.3 g / 11.15 g × 100

         %age Yield = 92.37 %

___________________________________________

Q.No. 2:

            A student makes sodium chloride by buming 2.3 grams of sodium in chlorine  gas. If the yield is 90%, how much sodium chloride is made?

Answer:

               Actual Yield =  5.785 g of NaCl

Solution:

               The balance chemical equation for given decomposition reaction is;

                                           2 Na + Cl₂ → 2 NaCl

Step 1: <u>Calculate Moles of Na:</u>

                Moles  =  Mass / M.Mass

                Moles  =  2.3 g / 23 g/mol

                Moles  =  0.10 moles of Na

Step 2: <u>Calculate theoretical amount of NaCl produced;</u>

According to equation,

              2 moles of Na produced  =  2 moles of NaCl

So,

           0.10 moles of Na will produce  =  X moles of NaCl

Solving for X,

                     X  =  0.10 mol × 2 mol / 2 mol

                     X  =  0.10 mol of NaCl

Also,

         Mass  =  Moles × M.Mass

         Mass  =  0.10 mol × 58.44 g/mol

         Mass  =  5.844 g of NaCl

Step 3: <u>Calculate Actual Yield as;</u>

         %age Yield  =  Actual Yield / Theoretical Yield × 100

Or,

         Actual Yield  =  %age Yield × Theoretical Yield ÷ 100

         Actual Yield  =  99 × 5.844 g ÷ 100

         Actual Yield =  5.785 g of NaCl

___________________________________________

Q.No. 3:

            For the chemical reaction Mg(s) + 2 HCl (aq) → H₂ (g) + MgCl₂ (aq) calculate the  % yield if 100 grams of magnesium react with excess HCl to produce 310 grams of MgCl₂.

Answer:

               %age Yield = 79.13 %

Solution:

               The balance chemical equation for given decomposition reaction is;

                                           Mg + 2 HCl → MgCl₂ + H₂

Step 1: <u>Calculate Moles of Mg:</u>

                Moles  =  Mass / M.Mass

                Moles  =  100 g / 24.30 g/mol

                Moles  =  4.11 moles of Mg

Step 2: <u>Calculate theoretical amount of MgCl₂ produced;</u>

According to equation,

              1 mole of Mg produced  =  1 mole of MgCl₂

So,

           4.11 moles of Mg will produce  =  X moles of MgCl₂

Solving for X,

                     X  =  4.11 mol × 1 mol / 1 mol

                     X  =  4.11 mol of MgCl₂

Also,

         Mass  =  Moles × M.Mass

         Mass  =  4.11 mol × 95.21 g/mol

         Mass  =  391.73 g of MgCl₂

Step 3: <u>Calculate %age Yield as;</u>

         %age Yield  =  Actual Yield / Theoretical Yield × 100

         %age Yield  =  310.0 g / 391.73 g × 100

         %age Yield = 79.13 %

5 0
4 years ago
What are the 3 types of chemical reactions?
den301095 [7]

Answer:

Synthesis reactions. Decomposition reactions. Combustion reactions.

Explanation:

Synthesis reactions. - Two or more reactants combine to make 1 new product

Decomposition reactions. - A single reactant breaks down to form 2 or more products.

Combustion reactions. - A single element or compound combines with oxygen gas releasing energy. This rapid oxidation is called burning.

4 0
3 years ago
What two things will you consistently do to maintain your mental health?<br>​
3241004551 [841]

Answer:

Eat healthy food  and exercise daily also undertake good healthcare

There are some special exercises that help to increase brain strength you can do them

5 0
3 years ago
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