Question

A fitness center currently has 320 members. Monthly memberships fees are $45. The manager of the fitness center has determined that each time the membership increases by $5, approximately 10 members leave and go to a different gym.
Write a equation that can be used to find the revenue of the fitness center in dollars,y, after x price increases of $5

Answer 1

Answer:

The required equation :

$y=(320-10x)(45+5x)=14400+1150x-50x^2$  

Step-by-step explanation:

Given : A fitness center currently has 320 members. Monthly memberships fees are $45. The manager of the fitness center has determined that each time the membership increases by $5, approximately 10 members leave and go to a different gym.  

To write : A equation that can be used to find the revenue of the fitness center in dollars,y, after x price increases of $5.

Solution :

Revenue is defined by the amount or price during specific period.

Let x be the number of months,

y be the revenue of the fitness center.

The number of members in the fitness center is 320 but after increasing $5 10 members leave.

So, the total member after increment in x months are $320-10x$

Monthly memberships fees are $45.

The manager of the fitness center has determined that each time the membership increases by $5.

The price of monthly membership after increment is $45+5x$

So, The equation which gave the revenue of the fitness center is

$y=(320-10x)(45+5x)$      

$y=14400+1600x-450x-50x^2$      

$y=14400+1150x-50x^2$