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3 years ago

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What does the electron do in an atom?

1 answer:

stepan [7]3 years ago

3 0

Answer:

Electrons are the negatively charged particles of an atom.Together,all of the electrons of a atom create a negitive charge that balances the positive charge of the protons

Explanation:

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The magnitude of Earth’s magnetic field is about 0.5 gauss near Earth’s surface. What’s the maximum possible magnetic force on a

vampirchik [111]

Answer:

$F = 1.5 \times 10^{-16} N$

this force is $1.68 \times 10^{13}$ times more than the gravitational force

Explanation:

Kinetic Energy of the electron is given as

$KE = 1 keV$

$KE = 1 \times 10^3 (1.6 \times 10^{-19}) J$

$KE = 1.6 \times 10^{-16} J$

now the speed of electron is given as

$KE = \frac{1}{2}mv^2$

now we have

$v = \sqrt{\frac{2 KE}{m}}$

$v = 1.87 \times 10^7 m/s$

now the maximum force due to magnetic field is given as

$F = qvB$

$F = (1.6\times 10^{-19})(1.87 \times 10^7)(0.5 \times 10^{-4})$

$F = 1.5 \times 10^{-16} N$

Now if this force is compared by the gravitational force on the electron then it is

$\frac{F}{F_g} = \frac{1.5 \times 10^{-16}}{9.1 \times 10^{-31} (9.8)}$

$\frac{F}{F_g} = 1.68 \times 10^{13}$

so this force is $1.68 \times 10^{13}$ times more than the gravitational force

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3 years ago

What question did use of a telescope by hubble answer A) Is earth the center of the universe B) Is the sun the center of the uni

cestrela7 [59]

Answer: C

Explanation:

3 0

2 years ago

Read 2 more answers

A 49.0 kg wheel, essentially a thin hoop with radius 0.730 m, is rotating at 114 rev/min. It must be brought to a stop in 22.0 s

belka [17]

Explanation:

Mass of the wheel, m = 49 kg

Radius of the hoop, r = 0.73 m

Initial angular speed of the wheel, $\omega_i=114\ rev/min = 11.93\ rad/s$

Final angular speed of the wheel, $\omega_f=0$

Time, t = 22 s

(a) If I is the moment of inertia of the hoop. It is equal to,

$I=mr^2$

$I=49\times (0.73)^2$

$I=26.11\ kg-m^2$

We know that the work done is equal to change in kinetic energy.

$W=\Delta E$

$W=\dfrac{1}{2}I(\omega_f^2-\omega_i^2)$

$W=-\dfrac{1}{2}\times 26.11\times (11.93^2)$

W = -1858.05 Joules

(b) Let P is the average power. It is given by :

$P=\dfrac{W}{t}$

$P=\dfrac{1858.05\ J}{22\ s}$

P =84.45 watts

Hence, this is the required solution.

4 0

3 years ago

For an object with a given mass on Earth, calculate the weight of the object with the mass equal in magnitude to the number repr

leonid [27]

<u>Answer:</u> The weight of the object is 29.4 N

<u>Explanation:</u>

To calculate the weight of the object, we use the equation:

$W=m\times g$

where,

m = mass of the object = 3 kg

g = acceleration due to gravity = $9.8m/s^2$

Putting values in above equation, we get:

$W=3kg\times 9.8m/s^2\\\\W=29.4N$

Hence, the weight of the object is 29.4 N

6 0

3 years ago

How do I calculate initial speed by using the slope of a graph? The graph shows the relationship between S {(sin2ϴ)/g} and the a

Orlov [11]

The formula for slope is y=mx+b

3 0

2 years ago