We are given a series circuit with two light bulbs. In this case, the light bulbs act as resistors in series and the total resistance is:

That is the sum of all the resistances in series in the circuit. To determine the voltage we can use Ohm's law:

Where "R" is the total resistance and "I" is the current in the circuit. Replacing we get:
Answer:
The velocity is 31.25 m/s and direction is toward west.
Explanation:
Given that,
Distance 
Magnetic field 
Mass of proton 
Radius of earth 
Radius of orbit 


We need to calculate the speed
Using formula of magnetic field


Put the value into the formula


Hence, The velocity is 31.25 m/s and direction is toward west.
Answer:
You pull on the oars. By the third law, the oars push back on your hands, but that’s irrelevant to the motion of the boat. The other end of each oar (the blade) pushes against the water. By the third law, the water pushes back on the oars, pushing the boat forward.
Answer:
0.119 s
Explanation:
Given that

Lets take final speed of the softball after covering 4.8 m = V
We know that

Also We know that

Putting the value of V ,U and a in the previous equation We get

Therefore slide time will be 0.119 s