Explanation:
The given data is as follows.
m = 5000 kg, h = 800 km = ![0.8 \times 10^{6} m](https://tex.z-dn.net/?f=0.8%20%5Ctimes%2010%5E%7B6%7D%20m)
, r = R + h = ![7.17 \times 10^{6} m](https://tex.z-dn.net/?f=7.17%20%5Ctimes%2010%5E%7B6%7D%20m)
kg, G = ![6.67 \times 10^{-11} Nm^{2}/kg^{2}](https://tex.z-dn.net/?f=6.67%20%5Ctimes%2010%5E%7B-11%7D%20Nm%5E%7B2%7D%2Fkg%5E%7B2%7D)
As we know that,
![\frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%5E%7B2%7D%7D%7Br%7D%20%3D%20%5Cfrac%7BGmM_%7Be%7D%7D%7Br%5E%7B2%7D%7D)
v = ![\sqrt{\frac{GM_{e}}{r^{2}}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BGM_%7Be%7D%7D%7Br%5E%7B2%7D%7D%7D)
And, it is known that formula to calculate angular velocity is as follows.
![\omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cfrac%7Bv%7D%7Br%7D%20%3D%20%5Csqrt%7B%5Cfrac%7BGM_%7Be%7D%7D%7Br%5E%7B3%7D%7D%7D)
v = ![\sqrt{\frac{GM_{e}}{r^{3}}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BGM_%7Be%7D%7D%7Br%5E%7B3%7D%7D%7D)
= ![\sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B6.67%20%5Ctimes%2010%5E%7B-11%7D%20Nm%5E%7B2%7D%2Fkg%5E%7B2%7D%20%5Ctimes%205.98%20%5Ctimes%2010%5E%7B-24%7D%20kg%5E%7B-2%7D%7D%7B%287.17%20%5Ctimes%2010%5E%7B6%7D%20m%29%5E%7B3%7D%7D%7D)
= ![1.0402 \times 10^{-3} rad/s](https://tex.z-dn.net/?f=1.0402%20%5Ctimes%2010%5E%7B-3%7D%20rad%2Fs)
Thus, we can conclude that speed of the satellite is
.
The answer for this change in the magnitude of momentum is the same for both because momentum is always conserved so both vehicles have the identical change.
So for determining who has the greater change in kinetic energy, momentum (P) = mv so P^2 = m^2 v^2 P^2 / 2m = 1/2 m v^2 = energy So the weightier the mass the smaller the energy change for the same momentum change so in here, the car has a greater change in kinetic energy.
Answer:p Pulls down on the object changing inertia creating an affect in momentum
Answer:
greater with the brick wall
Explanation:
the impulse does not depend whether its a haystack or a brick wall because impulse is the products mass and velocity.
The problem wants to compute how long does it take for the acceleration to occur if a car travelling at 7m/s accelerates uniformally at 2.5 m/s^2 to reach a speed of 12 m/s and base on that, the time duration would be 2 seconds. I hope this would help