Answer:
The equilibrium position will shift towards the left hand side or reactants side
Explanation:
Decreasing the volume (increasing the pressure) of the system will shift the equilibrium position towards the lefthand side or reactants side. This is because, decreasing the volume (increasing the pressure) implies shifting the equilibrium position towards the side having the least number of moles.
There are two moles of reactants and a total of three moles of products(total). Hence decreasing the volume and increasing the pressure of the gas phase reaction will shift the equilibrium position towards the lefthand side.
Friction? For example, like when a car's tires skid on rough concrete.
<span>Volume of cylinder = pi*r*2*L
As, from the above formula,volume is directly proportional to length,
So, if we increase in length also increases in volume by 0.22%
we know
</span><span>density=<span><span>mass/</span><span>volume
As, density is inversely proportional to volume it means increasing in volume decreases the density by 50.22%
</span></span></span>
I assume that the force of 20 N is applied along the direction of motion and was applied for the whole 6 meters, the formula of work is this; Work = force * distance * cosθ where θ is zero degrees. Plugging in the data to the formula; Work = 20 N * 6 m * cos 0º.
Work = 20 N * 6 m * 1
Work = 120 Nm
Work = 120 joules
Hope this helps!
Answer:
E) d/sqrt2
Explanation:
The initial electric force between the two charge is given by:

where
k is the Coulomb's constant
q1, q2 are the two charges
d is the separation between the two charges
We can also rewrite it as

So if we want to make the force F twice as strong,
F' = 2F
the new distance between the charges would be

so the correct option is E.