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Elena-2011 [213]
3 years ago
6

Compare and contrast the terms vaporizing and condensation.

Physics
1 answer:
JulsSmile [24]3 years ago
5 0
The terms are both about changing states. Vaporizing is when you heat something up into a vapor; condensation is when you lower a vapors temperature to make it become a liquid state.
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A hammer strikes one end of a thick iron rail of length 5.60 m. A microphone located at the opposite end of the rail detects two
never [62]

Answer:

A) The wave that travels through the rail reaches the microphone first.

B) separation in time between the arrivals of the two pulses is 0.01539 seconds.

Explanation:

Detailed explanation and calculation is shown in the image below

4 0
3 years ago
Tyrone, an 85-kg teenager, runs off the end of a horizontal pier and lands on a free-floating 130-kg raft that was initially at
Ghella [55]

Answer:u=4.04 m/s

Explanation:

Given

Mass m=85 kg

mass of Raft M=130 kg

velocity of raft and man  v=1.6 m/s

Let initial speed of Tyrone is u

Conserving Momentum as there is no external Force

mu=(M+m)v

85\times u=(85+130)\cdot 1.6

u=\frac{215}{85}\cdot 1.6

u=2.529\cdot 1.6=4.04 m/s  

4 0
3 years ago
List three ways in which the study of science has made modern life different from that of 100 years ago​
stealth61 [152]
Life Expectancy Was Shorter
Trains were faster to ride
The population explosion was not as on date
8 0
2 years ago
A 73-kg Norwegian olympian ski champion is going down a hill sloped at 39 ◦ . The coefficient of kinetic friction between the sk
bazaltina [42]

Answer:

Explanation:

net force on the skier = mg sin 39 - μ mg cos39

mg ( sin39 - μ cos39 )

= 73 x 9.8 ( .629 - .116)

= 367 N

impulse = net force x time = change in momentum .

= 367 x 5 = 1835 kg m /s

velocity of the skier after 5 s = 1835 / 73

= 25.13 m /s

b )

net force becomes zero

mg ( sin39 - μ cos39 ) = 0

μ = tan39

= .81

c )

net force becomes zero , so he will continue to go ahead with constant speed of 25.13 m /s

so he will have speed of 25.13 m /s after 5 s .

5 0
2 years ago
Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1150 kg and was approaching at
devlian [24]
Force acting during collision is internal so momentum is conserve so (initial momentum = final momentum) in both directions Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1150 kg and was approaching at 5.00 m/s due south. The second car has a mass of 750 kg and was approaching at 25.0 m/s due west. Let Vx is and Vy are final velocities of car in +x and +y direction respectively. initial momentum in +ve x (east) direction = final momentum in +ve x direction (east)

- 750*25 + 1150*0 = (750+1150)
Vx initial momentum in +ve y (north) direction = final momentum in +ve y direction (north)

750*0 - 1150*5 = (750+1150)
Vy from here you can calculate Vx and Vy so final velocity V is


<span>V=<span>(√</span><span>V2x</span>+<span>V2y</span>) 
</span>
and angle make from +ve x axis is

<span>θ=<span>tan<span>−1</span></span>(<span><span>Vy</span><span>Vx</span></span>)

</span><span> kinetic energy loss in the collision = final KE - initial KE</span>
5 0
3 years ago
Read 2 more answers
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