The question is incomplete, so I tried to find a similar problem online. It is shown in the attached picture. The reaction is
PCl₃ + Cl₂ ⇆ PCl₅
Then, we use the ICE (Initial-Change-Excess) approach as follows:
PCl₃ + Cl₂ ⇆ PCl₅
I 0.5 0.5 0.3
C -x -x +x
E 0.5-x 0.5-x 0.3+x
Total pressure: 0.5 - x + 0.5 - x + 0.3 + x = 1.3
Kp = [PCl₅]/[PCl₃][Cl₂]
0.18 = (0.3+x)/(0.5-x)²
Solving for x,
x= 0.21
Partial pressures would be:
<em>PCl₃ = 0.5 - 0.21 = 0.29 atm</em><em>Cl₂ = 0.5 - 0.21 = 0.29 atm</em><em>PCl₅ = 0.3+0.21 = 0.51 atm</em>
Answer:
K.E = 19125 j
Explanation:
Given data:
Mass = 150 Kg
Speed of car = 15 m/s
K.E = ?
Solution:
Formula:
K.E = 1/2 (mv²)
K.E = Kinetic energy
m = given mass
V = speed
now we will put the values in formula.
K.E = 1/2 (mv²)
K.E = 1/2 (150 Kg) (15²)
K.E = 1/2 150 Kg × 225 m²/s²
K.E = 0.5 × 225 m²/s² ×150 Kg
K.E = 19125 j
Answer:
Some of the major biogeochemical cycles are as follows: (1) Water Cycle or Hydrologic Cycle (2) Carbon-Cycle (3) Nitrogen Cycle (4) Oxygen Cycle. The producers of an ecosystem take up several basic inorganic nutrients from their non-living environment.
Explanation:
Answer:
Molar mass and Mass
Explanation:
The relationship between mass and number of moles is given as;
Number of moles = Mass / Molar mass
Mass = 1.6 g
Molar mass of HCl = ( 1 + 35.5 ) = 36.5 g/mol
Number of moles = 1.6 g / 36.5 g/mol
Number of moles = 0.0438 mol
Missing question: what is the density of 53.4 wt% aqueous NaOH if 16.7 mL of the solution diluted to 2.00L gives 0.169 M NaOH?
Answer is: density is 1.52 g/mL.
c₁(NaOH) = ?; molarity of concentrated sodium hydroxide.
V₁(NaOH) = 16.7 mL; volume of concentrated sodium hydroxide.
c₂(NaOH) = 0.169 M; molarity of diluted sodium hydroxide.
V₂(NaOH) = 2.00 L · 1000 mL/L = 2000 mL; volume of diluted sodium hydroxide.
Use equation: c₁V₁ = c₂V₂.
c₁ = c₂V₂ / V₁.
c₁ = 0.169 M · 2000 mL / 16.7 mL.
c₁(NaOH) = 20.23 M.
m(NaOH) = 20.23 mol · 40 g/ml.
m(NaOH) = 809.53 g.
The mass fraction is the ratio of one substance (in this example sodium hydroxide) with mass to the mass of the total mixture (solution).
Make proportion: m(NaOH) : m(solution) = 53.4 g : 100 g.
m(solution) = 1516 g in one liter of solution.
d(solution) = 1516 g/L = 1.52 g/mL.
