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krek1111 [17]
2 years ago
10

What are electrolytes

Chemistry
1 answer:
Alex777 [14]2 years ago
3 0
An electrolyte is a substance that produces an electrically conducting solution when dissolved in a polar solvent, such as water. The dissolved electrolyte separates into cations and anions, which disperse uniformly through the solvent. Electrically, such a solution is neutral. 

Hope this helps!!
:)
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What Is the Connection Between Sulfuric Acid and Hydrochloric Acid?
d1i1m1o1n [39]
They are both strong, corrosive acids. Hydrochloric acid can be synthesize using table salt and sulfuric acid.
7 0
2 years ago
Uranium – 235 has a half-life of 713 million years. Would uranium – 235 or carbon – 14 be more useful for dating Cambrian time e
kenny6666 [7]
Uranium-235 would be more useful for dating in Cambrian time because Cambrian time was 540 million years ago while the half life of carbon-14 is only 5,730 years
Hope this helps
6 0
2 years ago
The formula HCl stands for ____.
serious [3.7K]
HCl :

hydrochloric acid

answer A

hope this helps!
7 0
2 years ago
46g of a mineral contained 16g copper, 14g iron and 16g sulphur. Calculate the empirical
pochemuha

Answer:

CuFeS2

Explanation:

Calculate the moles of each substance by doing moles= mass/relative atomic mass. you should get 0.25 moles of copper and iron and 0.5 moles of sulfur. Then divide all of those numbers by 0.25 (as its the lowest value) you should get 1 for copper and iron and 2 for sulfur. This represents the ratio that they are in within the mineral.

7 0
3 years ago
a factor of 8, it means that A is now only 1/8 of its original concentration. A first order reaction, where A → products, has a
Trava [24]

Answer:

It takes 1.32x10⁻⁷s for the concentration of A to fall by a factor of 8

Explanation:

The equation that represents a first-order kinetics is:

Ln ([A] / [A]₀] = -kt

<em>Where [A] is actual concentration, [A]₀ is initial concentration, K is rate constant (For the given problem, 1.57x10⁷s⁻¹ and t is time.</em>

<em />

As you want the time when you have [A] in a factor of 8 = [A] / [A]₀ = 1/8

Replacing:

Ln ([A] / [A]₀] = -kt

Ln (1/8) = -1.57x10⁷s⁻¹*t

t = 1.32x10⁻⁷s

<h3>It takes 1.32x10⁻⁷s for the concentration of A to fall by a factor of 8</h3>

4 0
3 years ago
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