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NemiM [27]
3 years ago
10

How many moles are in 6.80 x 10^23 atoms of gold, Au?

Chemistry
1 answer:
frosja888 [35]3 years ago
8 0

Answer:

1.13 moles Au

Explanation:

Moles Au = 6.80x10²³atoms / 6.023x10²³atoms/mole = 1.13 moles Au

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bezimeni [28]
Your answer is correct.

2NaCl(s) ---T--> 2Na(s) + Cl2(g)

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4 years ago
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The most probable mechanism of reactivity for the solvolysis of 2-chloro-norbornane is
velikii [3]

The rate determining step for the reactivity for the solvolysis of 2-chloro-norbornane depends only on the decomposition of a single molecular species which is the 2-chloro-norbornane itself. For unimolecular reactions, the mechanism pathway being followed is that of an SN1 mechanism.

 

Answer:

<span>SN1 mechanism</span>

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4 years ago
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SOVA2 [1]

Answer:

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Explanation:

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3 years ago
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Dmitrij [34]

-59 kj/mol exothermic

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4 years ago
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This is due at 2:00 am today. I only have a few points. No links please I need a real answer.
GuDViN [60]

Answer:

7.5 g of AlCl3

Explanation:

The given equation is;

NaOH + AlCl3 --> Al(OH)3 + NaCI.

By inspection, it is not balanced because OH and Clare not equal on both sides of the equation.

Thus, let's make them equal by balancing the equation.

Cl has 3 on the left, so we will make it to have 3 on the right. Same thing with OH on the right and we will make it to have 3 on the left. Thus:

3NaOH + AlCl3 --> Al(OH)3 + 3NaCI

We can see that;

NaOH has 3 moles

While AlCl3 has 1 mole

Thus, to find how many grams of AlCl3 will be required to completely react with 2.25g of NaOH ;

2.25g of NaOH × (3 moles NaOH/39.997 g/mol of NaOH) × (1 mole of AlCl3/3 moles of NaOH) × (133.34 g/mol of AlCl3/1 mol AlCl3) = 7.5 g of AlCl3

5 0
3 years ago
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