How many gallon are there in 85.00 L?

Which things from the image make up the pond community?

olga55 [171]

D because community is also full of abiotic factors

4 0

3 years ago

Given the following balanced equation at 120°C: A(g) + B(g) ⇋ 2 C(g) + D(s)(a) At equilibrium a 4.0 liter container was found to

BlackZzzverrR [31]

Answer:

a) kc = 0,25

b) [A] = 0,41 M

c) [A] = 0,8 M

[B] =0,2 M

[C] = 0,2M

Explanation:

The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.

Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium.

If global reaction is:

A(g) + B(g) ⇋ 2 C(g) + D(s)

The kc = $\frac{[C]^2}{[A][B]}$

a) The concentrations of each compound are:

[A] = $\frac{1,60 moles}{4,0 L}$ = 0,4 M

[B] = $\frac{0,40 moles}{4,0 L}$ = 0,1 M

[C] = $\frac{0,40 moles}{4,0 L}$ = 0,1 M

kc = $\frac{[0,1]^2}{[0,4][0,1]}$ = 0,25

b) The addition of B and D in the same amount will, in equilibrium, produce these changes:

[A] = $\frac{1,60-x moles}{4,0 L}$

[B] = $\frac{0,60-x moles}{4,0 L}$

[C] = $\frac{0,60+2x moles}{4,0 L}$

0,25 = $\frac{[0,60+2x]^2}{[1,60-x][0,60-x]}$

You will obtain

3,75x² +2,95x +0,12 = 0

Solving

x =-0,74363479081119 → No physical sense

x =-0,043031875855476

Thus, concentration of A is:

$\frac{1,60-(-0,04 moles)}{4,0 L}$ = 0,41 M

c) When volume is suddenly halved concentrations will be the concentrations in equilibrium over 2L:

[A] = $\frac{1,60 moles}{2,0 L}$ = 0,8 M

[B] = $\frac{0,40 moles}{2,0 L}$ = 0,2 M

[C] = $\frac{0,40 moles}{2,0 L}$ = 0,2M

I hope it helps!

8 0

4 years ago

Read 2 more answers

A researcher is using a small molecule as an inhibitor to manipulate a signaling pathway. This inhibitor prevents phosphorylatio

Ganezh [65]

Answer:

The complete question is:

A researcher is using a small molecule inhibitor to manipulate a signaling pathway. This inhibitor prevents phosphorylation and most likely targets

a: phosphatase.

b: ligand-gated ion channel.

c: G protein-coupled receptor.

d: G-protein.

e: receptor kinase.

The correct answer is:

e: receptor kinase.

Explanation:

Kinase is the enzyme that add phosphate groups by transferring them from molecules having high energy (i.e. ATP) to target compound and the process of adding phosphate groups to the target compound is called phosphorylation.

In light of the above explanation, it is clear that kinase is the type of enzyme that involves in phosphorylation therefore, if an inhibitor prevents phosphorylation, it will automatically targets receptor kinase to inhibit the process of phosphorylation.

3 0

4 years ago

Predict the chemical formula of butyne, having one carbon-carbon triple bond.

Svet_ta [14]

Butyne is the alkyne with four carbon atoms, and, as the question states, it has one carbon-carbon triple bond. The general formula of an alkyne is CnH2n-2, that means that when there are 2 carbons the formula is C2H2, when there are 3 carbons the formula is C3H4, and when there are 4 carbons the formula is C4H6. So, butyne is C4H6 or " CH3-C (triple bond) C - CH3" (note that I wrote the phrase triple bond between the two Cs in the middle of the formula because there is no way to draw the three hyphens stacked one over other").

3 0

3 years ago

Who said

Ymorist [56]

Awnser: The awnser would be (D) Thomas

Explanation:

Use Quizlet

7 0

3 years ago