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elixir [45]
3 years ago
6

Please hurry!!! And help!!

Chemistry
2 answers:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

D

Explanation:

natali 33 [55]3 years ago
4 0

Answer:

D

Explanation:

Because it is true

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What is an isotope? list the isotopes of hydrogen in order from lighter to heavier. which is the most common among them?
malfutka [58]
Isotopes= a group of atoms with the same no. of protons , but different no. of neutrons

Hydrogen isotopes

^1H\implies ^2H\implies ^3H

The name of the second isotope is deuterium and the name of the third isotope is tritium(radioactive).The most abundant isotope is ^1H
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3 years ago
The normal freezing point of a certain liquid
slavikrds [6]

Answer : The molal freezing point depression constant of liquid X is, 4.12^oC/m

Explanation :  Given,

Mass of urea (solute) = 5.90 g

Mass of liquid X (solvent) = 450 g  = 0.450 kg

Molar mass of urea = 60 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}}{\text{Molar mass of urea}\times \text{Mass of liquid X Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -0.5^oC

\Delta T^o = freezing point of liquid X = 0.4^oC

i = Van't Hoff factor = 1 (for non-electrolyte)

K_f = Molal-freezing-point-depression constant = ?

m = molality

Now put all the given values in this formula, we get

0.4^oC-(-0.5^oC)=1\times K_f\times \frac{5.90g}{60g/mol\times 0.450kg}

K_f=4.12^oC/m

Therefore, the molal freezing point depression constant of liquid X is, 4.12^oC/m

3 0
3 years ago
Which pair of molecules is not a polar bond?<br> OA. N-O<br> OO<br> B. C-O<br> C.O-H<br> OD. 0-0
hodyreva [135]
Od. 0-0 does not pair of the Molecules bid it’s polar bond due to certain pairs of molecules not being present within its presentations
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If this were a frictionless plane, what would be the ideal mechanical advantage?
slava [35]
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mechanical advantage (MA = slope/height)
here length of slope = 9Hheight = H                                                 so mechanical advantage = ---- 9H/H= 9                                                  
</span>
8 0
4 years ago
Classify the outcomes based on whether they are caused by adding or removing a reactant from a chemical reaction. The rate of th
Mama L [17]

Explanation: To study the outcomes, we will apply Le-Chatelier's principle.

Le-Chatelier's principle states that if there is any disturbance in the conditions of the dynamic equilibrium, the position of equilibrium will counteract the change.

1) The rate of the forward reaction increases.

This will happen when we add the reactant to a chemical reaction. According to Le-Chatelier's principle, by increasing the reactant, the equilibrium will shift in the direction where this effect is minimal. Hence, forward reaction is favored.

2) The rate of the revere reaction increases.

This will happen when we remove the reactant from a chemical reaction. According to Le-Chatelier's principle, by removing the reactant, the equilibrium will shift in the direction where this effect is minimal. Hence, reverse reaction is favored.

3) The concentration of product increases.

This will happen when we add reactants to a chemical reaction. According to  Le-Chatelier's principle, when we increase the concentration of reactants, the equilibrium will shift in the direction where this effect is minimal. Hence, the reaction will be in the forward direction which means that the concentration of product will increase.

4) The concentration of products decreases.

This will happen when we remove reactants from a chemical reaction. According to  Le-Chatelier's principle, when we decrease the concentration of reactants, the equilibrium will shift in the direction where this effect is minimal. Hence, the reaction will be in the reverse direction which means that the concentration of reactants will increase or concentration of products will decrease.

3 0
3 years ago
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