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Anettt [7]
3 years ago
5

1)The average lethal dose of Valium is 1.52 mg/kg of body weight. Estimate how many grams of Valium would be lethal for a 200.-l

b woman. Show all your calculations. (1lb = 453.6 g)
2) A patient in hospital is receiving the antibiotic amoxcillin IV at the rate of 50. mL/h. The IV contains 1.5 g of the antibiotic in 1000. mL. (IV stands for intravenous). Calculate the mg/min of the drip. Show all your calculations
Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
7 0

Answer:

1. 0.138g of valium would be lethel in the woman

2. 125mg/min is the drip of the patient

Explanation:

1. In a body, an amount of Valium > 1.52mg / kg of body weight would be lethal.

A person that weighs 200lb requires:

200<u>lb</u> × (453.6<u>g</u> / <u>1lb</u>) × (1kg / 1000<u>g</u>) = <em>90.72kg (Weight of the woman in kg)</em>

90.72kg × (1.52mg / kg) =

137.9mg ≡

<h3>0.138g of valium would be lethel in the woman</h3>

2. The IV contains 1.5g = 1500mg/mL.

If the patient is receiving 5.0mL/h, its rate in mg/h is:

5.0<u>mL</u>/h × (1500mg/<u>mL</u>) = 7500mg/h

Now as 1h = 60min:

7500mg/<u>h</u> × (1<u>h</u> / 60min) =

<h3>125mg/min is the drip of the patient</h3>
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How many electrons in an atom can share the quantum numbers n=3, l =2 and m subscript l = 2? (1 point)
Rama09 [41]

Answer : The number of electrons in an atom is, 2 electrons

Explanation :

As we know that there are four quantum numbers which are principle quantum number, azimuthal quantum number, magnetic quantum number and spin magnetic quantum number.

The Principle quantum number, n = 3. That means the electron present in the third energy level.

The Azimuthal quantum number, l = 2. That means the electron present in the d sub-shell.

The magnetic quantum number, m_l=2. That means it shows the 2 electrons present in one of the five 3d orbitals.

Hence, the number of electrons in an atom is, 2 electrons



8 0
3 years ago
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seropon [69]
What about? You must provide a question :)
8 0
3 years ago
For each of the following species: C2+ &amp; O2- Write the molecular orbital energy diagram and fill in the electrons Hint: in e
Tju [1.3M]

Molecular orbital energy is the energy associated with each electron in an atom or molecule.

It is expressed in electron volts (eV) and is determined by the electron's position in the atom or molecule. The molecular orbital energy diagram and fill-in the electrons are given here in each case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species.

C2+: Molecular Orbital Energy Diagram

1s2 2s2 2p2

σ2s*  ← 0 e-  

σ2s   ← 2 e-

σ2p*  ← 0 e-  

σ2p   ← 0 e-

π2p*  ← 0 e-  

π2p   ← 0 e-

Bond Order: 0

Stability: Unstable

Magnetism: Diamagnetic (no unpaired electrons)

O2-: Molecular Orbital Energy Diagram

1s2 2s2 2p4

σ2s*  ← 0 e-  

σ2s   ← 2 e-

σ2p*  ← 0 e-  

σ2p   ← 2 e-

π2p*  ← 0 e-  

π2p   ← 2 e-

Bond Order: 1

Stability: Stable

Magnetism: Paramagnetic (2 unpaired electrons)

For more questions like Molecular orbital theory click the link below:

brainly.com/question/20436223

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6 0
2 years ago
substance is dissolved in water and produces hydronium ions. This occurs when hydrogen ions move from the substance to associate
rjkz [21]
The answer is arrhenius acids...
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7 0
4 years ago
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The Weak Ionization constant (Ka) for HCOOH is equal to:<br><br><br> Please help me lol
iris [78.8K]

Answer:

Ka=\frac{[H^+][HCOO^-]}{[HCOOH]}

Explanation:

Hello,

In this case, the weak ionization reaction for formic acid is:

HCOOH(aq)\rightleftharpoons H^+(aq)+HCOO^-(aq)

In such a way, we simply recall the law of mass action in order to represent the weak ionization constant, Ka, for such process, by taking into account that the concentration of products is divided over the concentration of reactants as shown below:

Ka=\frac{[H^+][HCOO^-]}{[HCOOH]}

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8 0
4 years ago
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