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Marta_Voda [28]
4 years ago
10

What is the difference between naoh(s) and naoh(aq)?

Chemistry
2 answers:
Katena32 [7]4 years ago
8 0
NaOH (s) is in solid state and NaOH (aq) is an aqueous solution.
Lorico [155]4 years ago
6 0

Explanation:

In NaOH(s), the sodium hydroxide is present in solid state because (s) represents solid state of a substance.

This also means that there is strong force of attraction between sodium and hydroxide ions due to which they are bonded together.

In NaOH(aq), the sodium hydroxide is present in aqueous state because (aq) represents aqueous state.

This also means that in NaOH(aq) there are sodium and hydroxide ions are present in the solution.

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24H2S + 16HNO3 3Sg+ 16NO + 32H2O
jeka94

Answer:

24 sultur with 48hydrogen+16 hydrogen,nitrogen and 48 oxygen+16 nitrogen,16 oxygen+62hydrogen and 32 oxygen

Explanation:

3 0
3 years ago
How many grams of methane gas (CH4) need to be combusted to produce 12.5 L water vapor at 301 K and 1.1 atm? Show all of the wor
tangare [24]
Answer is: 4.45 grams of methane gas <span>need to be combusted</span>.
Balanced chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
Ideal gas law: p·V = n·R·T.<span>
p = 1.1 atm.
T = 301 K.
V(H</span>₂O) <span>= 12.5 L.
R = 0,08206 L·atm/mol·K.
</span>n(H₂O) = <span>1.1 atm · 12.5 L ÷ 0,08206 L·atm/mol·K · 301 K.
</span>n(H₂O) = 0.556 mol.
From chemical reaction: n(H₂O) : n(CH₄) = 2 : 1.
n(CH₄) = 0.556 mol ÷ 2 = 0.278 mol.
m(CH₄) = 0.278 mol · 16 g/mol.
m(CH₄) = 4.448 g.
4 0
3 years ago
The ksp of yttrium fluoride, yf3, is 8.62 × 10-21. calculate the molar solubility of this compound.
motikmotik

Answer:

The molar solubility of YF₃ is 4.23 × 10⁻⁶ M.

Explanation:

In order to calculate the molar solubility of YF₃ we will use an ICE chart. We identify 3 stages: Initial, Change and Equilibrium and we complete each row with the concentration of change of concentration. Let's consider the solubilization of YF₃.

       YF₃(s) ⇄ Y³⁺(aq) + 3 F⁻(aq)

I                       0               0

C                     +S            +3S

E                       S              3S

The solubility product (Ksp) is:

Ksp = [Y³⁺].[F⁻]³= S . (3S)³ = 27 S⁴

S=\sqrt[4]{Ksp/27} =\sqrt[4]{8.62 \times 10^{-21}  /27}=4.23 \times 10^{-6}M

6 0
4 years ago
A mixture of 18 % 18% disinfectant solution is to be made from 16 % 16% and 23 % 23% disinfectant solutions. How much of each so
jeka94

Answer: 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

Explanation:

According to the dilution law,

C_1V_1+C_2V_2=C_3V_3

where,

C_1 = concentration of ist disinfectant solution = 16 %

V_1 = volume of pure acid solution = x gallons

C_2 = concentration of another disinfectant solution= 23%

V_2 = volume of another acid solution= (28-x) gallons

C_3 = concentration of resulting disinfectant solution = 18 %

V_1 = volume of resulting acid solution = 28 gallons

16\times x+23\times (28-x)=18\times 28

x=20galllons

(28-x) = (28-20) = 8 gallons

Thus 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

7 0
3 years ago
What is the mass of an object if its density is 12.3 g/ml and it has a volume of 25 ml?
Virty [35]

density \:  =  \frac{mass}{volume}

mass = 12.3 × 25

= 307.5

approximately = 308 g

3 0
3 years ago
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