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mezya [45]
2 years ago
13

Which is true about metals used for jewelry, such as platinum and gold? A. They have low flammability. B. They have low reactivi

ty. C. They have high flammability. D. They have high reactivity.
Chemistry
2 answers:
Morgarella [4.7K]2 years ago
8 0

i think the answer is B. They have low reactivity.Hope this helped (:

Bingel [31]2 years ago
3 0

Answer:

B. They have low reactivity

Explanation:

Platinum and gold are noble metals used to make jewelry.

As noble metals have little reactivity, they have a greater resistance to undergo oxidation (loss of electrons) and reduction (gain of electrons), even with extreme temperature changes. It is very common to see steel wool oxidize (corrode, change color) in the kitchen, but we hardly see this happening with a gold ring or a platinum watch, for example.

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What is the volume of 4.00 moles of CO2 gas at STP?
likoan [24]

Answer:

89.6L

Explanation:

1mole of any gas occupies 22.4L. This simply means that,

1mole of CO2 occupies 22.4L at stp.

Therefore, 4moles of CO2 will occupy = 4 x 22.4 = 89.6L

8 0
3 years ago
Which equation correctly relates kinetic energy mass and velocity
jolli1 [7]

Answer: The equation for kinetic energy is \frac{1}{2}mv^2

Explanation:

Kinetic energy is the energy possessed by the virtue of object's motion. It is defined as the work needed to move a body of a given mass from rest to its velocity.

Mathematically,

K.E.=\frac{1}{2}mv^2

where,

m = mass of the body

v = velocity of the body.

Hence, above equation relates kinetic energy to the mass and velocity of the body.

3 0
3 years ago
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How do trends in the periodic table help predict the properties of an element
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8 0
2 years ago
PLZ HELP PLZ<br> NO WRONG ANSWERS
baherus [9]
The answer to the question is D
3 0
2 years ago
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Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
irina1246 [14]

Answer:

                     2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Explanation:

Step 1: Write the unbalanced chemical equation,

                          C₄H₁₀ + O₂ → CO₂ + H₂O

Step 2: Balance Carbon  Atoms;

As there are 4 carbon  atoms on left hand side and 1 carbon atoms on right hand site therefore, to balance them multiply CO₂ on right hand side by 4 i.e.

                            C₄H₁₀ + O₂ → 4 CO₂ + H₂O

Step 3: Balance Hydrogen Atoms;

There are 10 hydrogen atoms on left hand side and 2 hydrogen atom on right hand site therefore, to balance them multiply H₂O on left hand side by 5 i.e.

                            C₄H₁₀ + O₂ → 4 CO₂ +  5 H₂O

Step 4: Balance Oxygen Atoms:

Now there are 2 oxygen atoms in reactant side and 13 in product side. So, multiply O₂ by 6.5 i.e.

                            C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

Step 5: Remove fraction coefficients as,

Multiply whole equation by 2 to get rid of fractions i.e.

                            2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

7 0
2 years ago
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