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mezya [45]
3 years ago
13

Which is true about metals used for jewelry, such as platinum and gold? A. They have low flammability. B. They have low reactivi

ty. C. They have high flammability. D. They have high reactivity.
Chemistry
2 answers:
Morgarella [4.7K]3 years ago
8 0

i think the answer is B. They have low reactivity.Hope this helped (:

Bingel [31]3 years ago
3 0

Answer:

B. They have low reactivity

Explanation:

Platinum and gold are noble metals used to make jewelry.

As noble metals have little reactivity, they have a greater resistance to undergo oxidation (loss of electrons) and reduction (gain of electrons), even with extreme temperature changes. It is very common to see steel wool oxidize (corrode, change color) in the kitchen, but we hardly see this happening with a gold ring or a platinum watch, for example.

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A sample of glucose ( C6H12O6 ) of mass 8.44 grams is dissolved in 2.11 kg water. What is the freezing point of this solution? T
taurus [48]

Answer:

<em>- 0.0413°C ≅ - 0.041°C (nearest thousands).</em>

Explanation:

  • Adding solute to water causes the depression of the freezing point.

  • We have the relation:

<em>ΔTf = Kf.m,</em>

Where,

ΔTf is the change in the freezing point.

Kf is the freezing point depression constant (Kf = 1.86 °C/m).

m is the molality of the solution.

<em>Molality is the no. of moles of solute per kg of the solution.</em>

  • <em>no. of moles of solute (glucose) = mass/molar mass</em> = (8.44 g)/(180.156 g/mol) = <em>0.04685 mol.</em>

<em>∴ molality (m) = no. of moles of solute/kg of solvent</em> = (0.04685 mol)/(2.11 kg) = <em>0.0222 m.</em>

∴ ΔTf = Kf.m = (1.86 °C/m)(0.0222 m) = 0.0413°C.

<em>∴ The freezing point of the solution = the freezing point of water - ΔTf </em>= 0.0°C - 0.0413°C = <em>- 0.0413°C ≅ - 0.041°C (nearest thousands).</em>

6 0
3 years ago
How are fossils formed
creativ13 [48]
I am sure the answer is D
7 0
4 years ago
Which of the following numerical expressions gives the number of particles in 2.0 g of Ne?
mojhsa [17]

Answer:

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

Explanation:

Step 1: Data give

Mass of Ne = 2.0 grams

Molar mass of neon = 20.18 g/mol

Number of Avogadro = 6.0 *10^23 /mol

Step 2: Calculate number of moles of neon

Moles Ne = Mass of ne / Molar mass of ne

Moles Ne = 2.0 / 20.18 g/mol

Moles Ne = 0.099 moles

Step 3: Calculate nulber of particles

Number of particles = 6.022*10^23 / mol * 0.099 moles = 5.96 *10^22

Number of particles = 6.022*10^23 * (2.0g/ 20.18g/mol)

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

7 0
3 years ago
Which of these features is usually found where mountains exist next to the ocean?
Doss [256]

Fjords are usually found where mountains exist next to the ocean.

So the correct answer is C.

Hope this helps,

Davinia.

8 0
3 years ago
Read 2 more answers
What is the density of a 6 g of pure copper with a volume of 12 mL?
Sati [7]

Answer:

The density of copper is 0.5 g/mL

Explanation:

Given data:

Mass of copper = 6 g

Volume of copper = 12 mL

Density of copper = ?

Solution:

Formula:

d = m/v

d = density

m = mass

v = volume

d = 6 g/ 12 mL

d = 0.5 g/mL

Thus, the density of copper is 0.5 g/mL

5 0
3 years ago
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