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mezya [45]
3 years ago
13

Which is true about metals used for jewelry, such as platinum and gold? A. They have low flammability. B. They have low reactivi

ty. C. They have high flammability. D. They have high reactivity.
Chemistry
2 answers:
Morgarella [4.7K]3 years ago
8 0

i think the answer is B. They have low reactivity.Hope this helped (:

Bingel [31]3 years ago
3 0

Answer:

B. They have low reactivity

Explanation:

Platinum and gold are noble metals used to make jewelry.

As noble metals have little reactivity, they have a greater resistance to undergo oxidation (loss of electrons) and reduction (gain of electrons), even with extreme temperature changes. It is very common to see steel wool oxidize (corrode, change color) in the kitchen, but we hardly see this happening with a gold ring or a platinum watch, for example.

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What properties do molecules have that allow them to cross the bilayer without any help?
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NEED HELP ASAP!!! I just need to know the order
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3 years ago
At −15.0 ∘C , a common temperature for household freezers, what is the maximum mass of sucrose (C12H22O11) you can add to 1.50 k
nlexa [21]

Answer: The maximum mass of sucrose you can add is 4158.95 grams.

Explanation:

This is an example of freezing point depression. The formula for calculating this is the following:

ΔT = Kf . b . i

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Kf is the cryoscopic constant that is unique for each solvent

b is the molality of the solution (moles of solute per kg of solvent)

i is the Vant Hoff factor

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The Kf for water is known to be 1.853 K. Kg /mol

i is the number of particles the molecule is split to when ionized. Because sucrose doesn't ionize, its Vant Hoff factor is 1.

If we clear b from the ecuation:

b = ΔT/ Kf . i

b = 15K/ 1.853 K. Kg/mol . 1

b= 8.1 mol/kg

If we can add 8.1 moles to a kg of water before it freezes, we use cross multiplication to calculate how many we can add to 1.5 kg. The answer is 12.15.

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3 years ago
Consider the following equilibrium:H2CO3(aq) + H2O(l) H3O+(aq) + HCO3-1(aq).What is the correct equilibrium expression?
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<span>H2CO3(aq) + H2O(l) = H3O+(aq) + HCO3-1(aq)

Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>

4 0
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