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4 years ago

Plzz help me with these questions....!!!

Chemistry

1 answer:

exis [7]4 years ago

7 0

Answer:-

1) The pH of sodium bicarbonate will be around 8 as it is slightly basic. So the color will be blue.

2) The correct method for finding the pH of a solution is to use a dropper and drop wise add the solution to the pH paper lying on a glass tile. Hence the answer is 3.

3) HCl is an acid. The pH of HCl should be 1-2. NaOH is a base. It’s pH should be around 13-14.

KCl is a salt of a strong acid and strong base. It should have pH near 7. Distilled water has pH of 7. So the solutions with equal pH are KCl and distilled water. So the answer is number 4 (B and D).

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Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide.

prohojiy [21]

Answer:

2-methylene propylbenzene

Explanation:

The Wittig Reaction is a reaction that converts aldehydes and ketones into alkenes through reaction with a phosphorus ylide.

The ketone in this case is 1-phenylpropan-1-one. The provided phosphonium ylide is shown in the image attached. The reaction involves;

i) alkylation

ii) addition

The product of the major organic product of the reaction is 2-methylene propylbenzene.

4 0

3 years ago

What is the difference between constitutional isomers and confirmational isomers?

babymother [125]

Answer:

<h3>Constitutional Isomers are two molecules with the same composition but different constitution. Confirmational Isomers are two molecules with the same configuration but different confirmation.</h3>

Explanation:

4 0

4 years ago

Aggregate demand is everything produced while simple demand is one good

Sati [7]

I believe the answer is A. :)<span />

7 0

3 years ago

You are given a stock solution of 500.0 mL of 1.00M magnesium chloride solution. Calculate the volume of the stock solution you

alexgriva [62]

Answer:

$50\; \rm mL$ of the stock solution would be required.

Explanation:

Assume that a solution of volume $V$ contains a solute with a concentration of $c$ . The quantity $n$ of that solute in this solution would be:

$n = c \cdot V$ .

For the solution that needs to be prepared, $c = 0.20\; \rm M = 0.20\; \rm mol \cdot L^{-1}$ . The volume of this solution is $V = 250.0\; \rm mL$ . Calculate the quantity of the solute (magnesium chloride) in the required solution:

$\begin{aligned}n &= c \cdot V \\ &= 0.20\; \rm mol \cdot L^{-1} \times 250.0\; \rm mL \\ &= 0.20\; \rm mol \cdot L^{-1} \times 0.2500\; \rm L \\ &= 0.050\; \rm mol\end{aligned}$ .

Rearrange the equation $n = c \cdot V$ to find an expression of volume $V$ , given the concentration $c$ and quantity $n$ of the solute:

$\displaystyle V= \frac{n}{c}$ .

Concentration of the solute in the stock solution: $c(\text{stock}) = 1.00\; \rm M = 1.00\; \rm mol \cdot L^{-1}$ .

Quantity of the solute required: $n = 0.050\; \rm mol$ .

Calculate the volume of the stock solution that would contain the required $n = 0.050\; \rm mol$ of the magnesium chloride solute:

$\begin{aligned}& V(\text{stock}) \\ &= \frac{n}{c(\text{stock})} \\ &= \frac{0.050\; \rm mol}{1.00\; \rm mol \cdot L^{-1}} \\ &= 0.050\; \rm L \\ &= 50\; \rm mL\end{aligned}$ .

3 0

3 years ago

the molar solubility of Zn(OH)2 is 5.7x 10^-3 mol/L at a certain temperature. Calculate the value of Ksp for Zn(OH)2 at this tem

Alex

Answer:

Ksp = 7.4x10⁻⁷

Explanation:

Molar solubility of a substance is defined as the amount of moles of that can be dissolved per liter of solution.

Ksp of Zn(OH)₂ is:

Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻

Ksp = [Zn²⁺] [OH⁻]²

And the molar solubility, X, is:

Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻

⇄ X + 2X

<em>Because X are moles of substance dissolved.</em>

<em>Ksp = </em>[X] [2X]²

Ksp = 4X³

As molar solubility, X, is 5.7x10⁻³mol/L:

Ksp = 4X³

Ksp = 4 (5.7x10⁻³mol/L)³

5 0

3 years ago