The structures of alkanes and alkynes are given below in the diagram.
In organic chemistry, when an organic compound contains atoms joined only by single covalent bonds, the compound is said to be saturated and this saturated hydrocarbons are known as alkanes. For example propane that is shown in the diagram attached below. When an organic compound contains carbon atoms joined by double(alkene) or triple(alkyne) covalent bonds, the compound is said to be unsaturated. For example propene and propyne as shown in the diagram.
Furthermore, the hydrocarbons that possess a set of carbon-carbon double covalent bonds,>C=C<, in their carbon chains form the homologous series called alkenes while those possessing a set of carbon-carbon triple covalent bond in their carbon chains form the alkyne series.
Learn more about alkanes and alkynes from the link given below.
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<u>Answer:</u> The average atomic mass of lithium is 6.9241 u.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
....(1)
- <u>For
isotope:</u>
Mass of
isotope = 6 u
Percentage abundance of
isotope = 7.59 %
Fractional abundance of
isotope = 0.0759
- <u>For
isotope:</u>
Mass of
isotope = 7 u
Percentage abundance of
isotope = 92.41%
Fractional abundance of
isotope = 0.9241
Putting values in equation 1, we get:
![\text{Average atomic mass of Lithium}=[(6\times 0.0759)+(7\times 0.9241)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20Lithium%7D%3D%5B%286%5Ctimes%200.0759%29%2B%287%5Ctimes%200.9241%29%5D)

Hence, the average atomic mass of lithium is 6.9241 u.
Answer:
The value of the equilibrium constant Kc is 5.45
Explanation:
The "Law of Mass Action" states:
"For a reversible reaction in chemical equilibrium at a given temperature, it is true that the product of the concentrations of the products raised to the stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients is a constant."
This constant was called the equilibrium constant. For a reaction:
aA + bB ⇄ cC + dD
the equilibrium constant Kc is:
![Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%2A%5BD%5D%5E%7Bd%7D%20%7D%7B%5BA%5D%5E%7Ba%7D%20%2A%5BB%5D%5E%7Bb%7D%20%7D)
In this case, the balanced reaction is:
2 H₂S → 2 H₂ + S₂
So, the equilibrium constant Kc is:
![Kc=\frac{[H_{2} ]^{2} *[S_{2} ] }{[H_{2} S]^{2} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_%7B2%7D%20%5D%5E%7B2%7D%20%2A%5BS_%7B2%7D%20%5D%20%7D%7B%5BH_%7B2%7D%20S%5D%5E%7B2%7D%20%20%7D)
The equilibrium concentrations are
- [H₂S] =0.25 M
- [H₂]= 0.88 M
- [S₂]= 0.44M
Replacing in the definition of equilibrium constant:

Solving:
Kc= 5.45
<u><em>The value of the equilibrium constant Kc is 5.45</em></u>
<u><em></em></u>
Answer:
period 6
Explanation:
If the lanthanides were inserted into the periodic table, they would go into periodic 6.
Their atomic number is between 57 - 71 from element lanthanum to lutetium.
- The elements in this period are 15 in number.
- They are also know as elements in the f-block.
The elements that makes up the series are:
Lanthanum
Cerium
Praseodymium
Neodymium
Promethium
Samarium
Europium
Gadolinium
Terbium
Dysprosium
Holmium
Erbium
Thulium
Ytterbium
Lutetium