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svetlana [45]
3 years ago
11

The Bohr model of an atom shows a nucleus with electrons circling around it. What does the Bohr model show that makes it a usefu

l model for understanding atoms?
Chemistry
1 answer:
Vlad [161]3 years ago
5 0
Bohr model of an atom illustrates a nucleus with electrons circling around it. This is a useful model for understanding atoms because this clarified that atoms are actually composed of three particles: protons, neutrons and electrons. The first two are located at the center part of an atom (nucleus), while electrons are located at the outer part. Valence electrons of an atom are also vital in the creation of different chemical compounds.
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12.53 (syn) show how each of these compounds can be produced from an alkene or alkyne. draw the appropriate alkene or alkyne and
sveta [45]

The structures of alkanes and alkynes are given below in the diagram.

In organic chemistry, when an organic compound contains atoms joined only by single covalent bonds, the compound is said to be saturated and this saturated hydrocarbons are known as alkanes. For example propane  that is shown in the diagram attached below. When an organic compound contains carbon atoms joined by double(alkene) or triple(alkyne) covalent bonds, the compound is said to be unsaturated. For example propene and propyne as shown in the diagram.

Furthermore, the hydrocarbons that possess a set of carbon-carbon double covalent bonds,>C=C<, in their carbon chains form the homologous series called alkenes while those possessing a set of carbon-carbon triple covalent bond in their carbon chains form the alkyne series.

Learn more about alkanes and alkynes from the link given below.

brainly.com/question/6818114

#SPJ4

3 0
1 year ago
Lithium, is used in dry cells and storage batteries and in high temperature lubricants, it has two naturally occurring isotopes,
erastovalidia [21]

<u>Answer:</u> The average atomic mass of lithium is 6.9241 u.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i ....(1)

  • <u>For _3^6\textrm{Li} isotope:</u>

Mass of _3^6\textrm{Li} isotope = 6 u

Percentage abundance of _3^6\textrm{Li} isotope = 7.59 %

Fractional abundance of _3^6\textrm{Li} isotope = 0.0759

  • <u>For _3^7\textrm{Li} isotope:</u>

Mass of _3^7\textrm{Li} isotope = 7 u

Percentage abundance of _3^7\textrm{Li} isotope = 92.41%

Fractional abundance of _3^7\textrm{Li} isotope = 0.9241

Putting values in equation 1, we get:

\text{Average atomic mass of Lithium}=[(6\times 0.0759)+(7\times 0.9241)]

\text{Average atomic mass of Lithium}=6.9241u

Hence, the average atomic mass of lithium is 6.9241 u.

7 0
3 years ago
How does freezing differ from deposition? ​
patriot [66]
  • Freezing - water moving from a liquid to a solid state.
  • Deposition - water moving from a vapor to a solid state.
8 0
3 years ago
Calculate the value of Key in the following reaction if the equilibrium concentrations are
MAXImum [283]

Answer:

The value of the equilibrium constant Kc is 5.45

Explanation:

The "Law of Mass Action" states:

"For a reversible reaction in chemical equilibrium at a given temperature, it is true that the product of the concentrations of the products raised to the stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients is a constant."

This constant was called the equilibrium constant. For a reaction:

aA + bB ⇄ cC + dD

the equilibrium constant Kc is:

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }

In this case, the balanced reaction is:

2 H₂S → 2 H₂ + S₂

So, the equilibrium constant Kc is:

Kc=\frac{[H_{2} ]^{2} *[S_{2} ] }{[H_{2} S]^{2}  }

The equilibrium concentrations are

  • [H₂S] =0.25 M
  • [H₂]= 0.88 M
  • [S₂]= 0.44M

Replacing in the definition of equilibrium constant:

Kc=\frac{(0.88 M)^{2} *0.44 M }{(0.25 M)^{2}  }

Solving:

Kc= 5.45

<u><em>The value of the equilibrium constant Kc is 5.45</em></u>

<u><em></em></u>

7 0
3 years ago
The Lanthanides are often be found below the Periodic Table so it will fit nicely on a textbook page. If they were inserted into
Annette [7]

Answer:

period 6

Explanation:

If the lanthanides were inserted into the periodic table, they would go into periodic 6.

Their atomic number is between 57 - 71 from element lanthanum to lutetium.

  • The elements in this period are 15 in number.
  • They are also know as elements in the f-block.

The elements that makes up the series are:

Lanthanum

Cerium

Praseodymium

Neodymium

Promethium

Samarium

Europium

Gadolinium

Terbium

Dysprosium

Holmium

Erbium

Thulium

Ytterbium

Lutetium

6 0
3 years ago
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