Question

Eric collected 1 1/3 times as many beads as Malik in the beginning. If Eric collected 48 more beads and Malik collected 13 more beads Eric would have twice as many beads as Malik How many beads did they collect all together

Answer 1

$E = \frac{4M}{3} \\E + 48 = 2(M+13)\\E + 48 = 2M + 26\\\frac{4M}{3}+48 = 2M + 26\\4M + 144 = 6M + 78\\2M = 66\\M = 33$

At the beginning, Malik had 33 beads, and Eric had 44, making them have 77 beads in total

At the end, Malik had (33 + 13 =) 46 beads and Eric had (44 + 48 = ) 92 beads.

Answer 2

Answer: they collected 77 beads all together.

Step-by-step explanation:

Let x represent the number of beads that Eric collected.

Let y represent the number of beads that Malik collected.

Eric collected 1 1/3(4/3) times as many beads as Malik in the beginning. This means that

x = 4y/3

If Eric collected 48 more beads and Malik collected 13 more beads, Eric would have twice as many beads as Malik. This means that

x + 48 = 2(y + 13)

x + 48 = 2y + 26 - - - - - - - - - - -1

Substituting x = 4y/3 into equation 1, it becomes

4y/3 + 48 = 2y + 26

Cross multiplying by 3, it becomes

4y + 144 = 6y + 78

6y - 4y = 144 - 78

2y = 66

y = 66/2 = 33

x = 4y/3 = (4 × 33)/3

x = 44

The total number of beads that they collected is

44 + 33 = 77 beads