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Alinara [238K]
3 years ago
5

Valid experiment for does water and oil mix

Chemistry
1 answer:
bonufazy [111]3 years ago
8 0

Answer: Water and oil cannot mix

Explanation:

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Mr Singh is cooking using wo pans of oiling water. Both pans are made of steel, but one pan has a much thicker base than the oth
Sholpan [36]

Answer:

See explanation

Explanation:

When either pan is heated, energy is transferred via conduction. Conduction is the process by which heat is transferred through a material, the average position of the particles remaining the same.

When the pans are heated, the particles in each pan vibrate faster and transfer this energy rapidly to neighboring particles.

The pan with a thicker base has more particles in it than the pan with lighter weight base. Note that, The rate of heat transfer is inversely proportional to the thickness of the material in question. Hence, the thicker the base, the more the number of particles present and the longer the time it takes for the food to cook.

6 0
3 years ago
If 0.580 moles of a monoprotic weak acid (ka = 7.4 10-5 is titrated with naoh, what is the ph of the solution at the half-equiva
Yuri [45]
<span><span>S is for soil,</span><span>cl (sometimes c) represents climate,</span><span>o organisms including humans,</span><span>r relief,</span><span>p parent material, or lithology, and</span><span>t time.</span></span>
7 0
3 years ago
How much heat is given off when 869 g iron bar cools from 94 degrees celsius to 5
melomori [17]

Answer:

Heat given off was -34.34kJ

Explanation:

Mass of iron bar = 869g

Initial temperature (T1) = 94°C

Final temperature (T2) = 5°C

Specific heat capacity of iron (c) = 0.444J/g°C

Heat energy (Q) = Mc∇T

Q = heat energy

c = specific heat capacity

∇T = change in temperature

M = mass of the substance

Q = mc∇T

∇T = T2 - T1

Q = Mc(T2 -T1)

Q = 869 * 0.444 * (5 - 94)

Q = 385.836 * -89

Q = -34339.404J

Q = -34.34kJ

The heat given of was -34.34kJ

4 0
3 years ago
What volume of 2.0 M HCl in mL will neutralize 25.0 mL of 1.00 M KOH?
MakcuM [25]
CaVa=CbVb
2xV=1X25
V=25/2
V=12.5ML
3 0
3 years ago
Find the pressure of a gas if the volume is 2.00 L, the temperature is 310 Kelvin and
kipiarov [429]

Answer:

25.42 atm

Explanation:

Data Given:

Volume of a gas ( V )= 2.00 L

temperature of a gas ( T ) =  310 K

number of moles (n) = 2​ mol

Pressure of a gas ( P ) = to be find

Solution:

Formula to be used

              PV= nRT

Rearrange the above formula

              P = nRT / V . . . . . . . . . . (1)

Where R is ideal gas constant

R = 0.08205 L atm mol⁻¹ K⁻¹

Put values in equation 1

                 P = nRT / V

                  P = 2 mol x 0.08205 L atm mol⁻¹ K⁻¹ x 310 k / 2 L

                  P = 50.84 L atm / 2 L

                  P = 25.42 atm

P ressure of gas (P) will be = 25.42 atm

7 0
3 years ago
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