A. 4. There are four sublevels in the n=4 level.
They are the <em>4s, 4p, 4d</em>, and <em>4f</em> sublevels.
Explanation:
the answer is letter A. mitosis
Answer:
Max. work done in 60 g of copper plated out is 200472.14 J
Explanation:
Given cell reaction is:
Standard reduction potential of Zn electrode (
) is 0.763 V.
Standard reduction potential of Cu electrode (
) is -0.337 V.
Copper acts as cathode and Zinc acts as anode.
Cell potential (E) = E° cathode - E° anode
= 0.763 - (-0.337)
= 1.10 V
formula for the work done is as follows:
Here, n is no. of electron involved in the reaction.
F(Faraday's constant) = 96500
In the given reaction, n = 2
Therefore, 212300 J work is done by reducting 1 mol of copper.
Copper given is 60 g.
Molecular mass of copper is 63.54 g/mol.
Max. work done in 60 g of copper plated out is:
Answer is: 0,327 g/l.
<span>Ideal gas law: pV = nRT.
</span><span>V - volume, the amount of space occupied by the gas.
</span><span>p - pressure ,1 atm = 760 torr = 760 mmHg.
</span><span>n - amount of substance.
</span>T - temperature, 273 K = 0°<span>C. T = 25 + 273 = 298K.
</span>R - ideal gas constant,<span> R = 0,08206 L</span>·atm/mol·K<span>.
</span>d(He) = M·p ÷ R·T.
d - density.
M - molar mass.
d(He) = 4g/mol · 2atm ÷ 298K · 0,08206 L·atm/mol·K = 0,327 g/l.
Ca as a limiting reactant
<h3>Further explanation</h3>
Given
8 g Calcium
50 g HCl
<h3>Required</h3>
Limiting reactant
Solution
Reaction
Ca + 2HCl → CaCl₂ + H₂
mol Ca (Ar = 40 g/mol) :
= mass : Ar
= 8 g : 40 g/mol
= 0.2
mol HCl (MW= 36.5 g/mol) :
= mass : MW
= 50 g : 36.5 g/mol
= 1.37
Mol : coefficient reactants :
Ca = 0.2/1 = 0.2
HCl = 1.37/2 = 0.685
Ca as a limiting reactant(smaller ratio)
