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Blizzard [7]
3 years ago
7

The low-grade iron ore taconite, which contains Fe3O4, is concentrated and made into pellets for processing. If one ton of tacon

ite pellets yields 545 lb. of iron, what percentage of the pellets is Fe304?
Chemistry
1 answer:
xenn [34]3 years ago
8 0

<u>Answer:</u> The percent composition of Fe_3O_4 in taconite is 37.6 %.

<u>Explanation:</u>

We are given:

Mass of taconite pellets = 1 ton = 907185 g      (Conversion factor: 1 ton = 907185 g)

Mass of iron produced = 545 lb = 247212 g    (Conversion factor:  1 lb = 453.6 g )

We know that:

Molar mass of iron = 55.85 g/mol

Molar mass of Fe_3O_4 = 231.53 g/mol

1 mole of Fe_3O_4 contains 3 moles of iron atom and 4 moles of oxygen atom

(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of Fe_3O_4

So, 247212 grams of iron will be produced from = \frac{231.53}{167.55}\times 247212=341611.43g of Fe_3O_4

To calculate the percentage of Fe_3O_4 in taconite, we use the equation:

\%\text{ composition of }Fe_3O_4=\frac{\text{Mass of }Fe_3O_4}{\text{Mass of taconite}}\times 100

Mass of taconite = 907185 g

Mass of Fe_3O_4 = 341611.43 g

Putting values in above equation, we get:

\%\text{ composition of }Fe_3O_4=\frac{341611.43g}{907185g}\times 100=37.6\%

Hence, the percent composition of Fe_3O_4 in taconite is 37.6 %.

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