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STatiana [176]
2 years ago
13

Acid rain is a dilute solution of acids that dissolve the calcium carbonate in limestone statues. Concentrated acids can dissolv

e a large piece of limestone in a few days. Statue breakdown due to acid rain can take decades, but statues with intricate carvings break down more quickly. Explain these observations in terms of reaction rates.
Chemistry
1 answer:
REY [17]2 years ago
7 0

Answer:

See the answer below

Explanation:

A weak solution of acid would gradually dissolve the calcium carbonate in limestone statues. For example, dilute sulphuric acid formed from the dissolution of SO2 in rainwater would react with calcium carbonate according to the following equation;

    H_2SO_4(aq)+CaCO_3(s)-->CaSO_4(s)+CO_2(g)+H_2O (l)

<em>Generally, the rate of any reaction depends on a host of factors such as temperature, pressure, presence of catalysts, and surface area of reactants. The higher the surface area of reactants, the higher the rate of reaction.</em>

In this case, the rate of reaction of the dilute acid and the calcium carbonate depends on the surface area of the calcium carbonate which happens to be the only solid reactant. <u>Statues with intricate carvings seem to break down more quickly than ordinary statues because they offer more surface area for reaction to take place</u>. The intricate carvings create more surface area for reactions when compared to statues without intricate carvings.

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How many atoms of oxygen are present in 7.51 grams of<br> glycine with formula C₂H5O2N?
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1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

However, the number of moles of oxygen in glycine can be calculated using the following expression:

Molar mass of C₂H5O2N = 75.07g/mol

Mass of oxygen in glycine = 32g/mol

Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine

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Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms

Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.

Learn more about number of atoms at: brainly.com/question/8834373

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