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Juliette [100K]
3 years ago
5

2NBr3 + 3NaOH = N2 +3NaBr + 3HOBr

Chemistry
2 answers:
WARRIOR [948]3 years ago
8 0

Answer:

NBr3

Explanation:

bija089 [108]3 years ago
6 0
The theoretical proportion is given by the balanced chemical equation:

2 mol NBr / 3 mol  Na OH

Then x mol NaOH / 40 mol NBr3 = 3mol NaOH/2 mol NBr3

Solve for x, x = 40 * 3/2 = 60 mol NaOH.

Given that there are 48 mol NaOH (less than 60) this is the limitant reactant and the other is the excess reactant.

Answer: NBr3..

 
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34.5 X 10^-11 grams of lead
5 0
3 years ago
Ronaldo experimentally determined the
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Explanation:

%error= error/actual density x100

0.050/0.890  x100

=5.62%

5 0
3 years ago
Consider the above unbalanced equation. What volume of CO2 is produced at 270. mm Hg and 38.5°C when 0.820 g of C4H8 reacts with
irinina [24]

Answer:

The volume of CO2 is 4.20 L

Explanation:

Step 1: Data given

Pressure = 270 mm Hg =  260 /760 = 0.355263 atm

Temperature : 38.5 °C = 311.65 K

Mass of C4H8 = 0.820 grams

Step 2: The balanced equation

C4H8 + 6O2 → 4CO2 + 4H2O

Step 3: Calculate moles C4H8

Moles C4H8 = mass C4H8 / molar mass C4H8

Moles C4H8 = 0.820 grams / 56.11 g/mol

Moles C4H8 = 0.0146 moles

Step 4: Caalculate moles CO2

For 1 mol C4H8 we need 6 moles O2 to produce 4 moles CO2 and 4 moles H2O

For 0.0146 moles we'll have 4*0.0146 = 0.0584 moles CO2

Step 6: Calculate Volume CO2

p*V = n*R*T

V = (n*R*T) /p

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⇒ with n = the moles of CO2 = 0.0584 moles

⇒ with R = the gas constant = 0.08206 L*atm / mol*K

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8 0
3 years ago
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Answer:

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The dark matter component has considerably more mass than the "visible" component of the Universe.

Explanation:

There are certain researchers who say that the appearance of dark matter was before the appearance of the big bang.

A relevant fact of this matter is that dark matter exerts gravity, and that gravity affects the movements of objects.

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3 0
4 years ago
What’s the correct answer
Fed [463]
The correct answer is: 
_________________________________________________________
    " F  and Br , because they are in the same group" .
_________________________________________________________
Note:
_________________________________________________________
Choice [B]:  "F and Br ; because they are in the same period" ; is incorrect; since  "F" and "Br" are not in the same "period" (that is, "row").
______________________________________________________
Choice [C]:  "Na and Mg; because they are in the same group {"column"} ;  is incorrect; since:  "Na" and "Mg are NOT in the same group {"column"].
_______________________________________________________
Choice [D]:  "Na and Mg" ; because they are in the same period {"row"}; is incorrect.  Note:  "Na" and "Mg" are, in fact,  in the same period {"row"}. However, as aforementioned, {Mg and Na} are not in the same group {"column".}.  

Note:  The similiarities in physical and chemistry properties among elements are determined and organized — or tend to be so—by "groups" {"columns"} — NOT by "periods" {rows}.  
______________________________________________________
3 0
4 years ago
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