3 years ago

2NBr3 + 3NaOH = N2 +3NaBr + 3HOBr

Chemistry

2 answers:

WARRIOR [948]3 years ago

8 0

Answer:

NBr3

Explanation:

bija089 [108]3 years ago

6 0

The theoretical proportion is given by the balanced chemical equation:

2 mol NBr / 3 mol Na OH

Then x mol NaOH / 40 mol NBr3 = 3mol NaOH/2 mol NBr3

Solve for x, x = 40 * 3/2 = 60 mol NaOH.

Given that there are 48 mol NaOH (less than 60) this is the limitant reactant and the other is the excess reactant.

Answer: NBr3..

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