The Molarity
concentration is expressed in units of moles / L. So let us first determine the
number of moles of CH3OH, and then divide that amount by the total volume of
0.230 L of solution.<span>
<span>To determine the number of moles of CH3OH, divide the weight
in grams of CH3OH by the molecular weight of CH3OH: (MW of CH3OH = 32
g / mol)</span>
number of moles = 16.8 g / (32 g / mol)</span>
number of moles = 0.525
mol CH3OH <span>
Then we calculate for molarity:</span>
Molarity = 0.525 mol
CH3OH / .230 L
Molarity = 2.2826 mol /
L
<span>Molarity = 2.28 M</span>
Answer:
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Explanation:
Answer:
2.1 M is the molarity of the HCl solution.
Explanation:
Molarity of HCl solution = 
Volume of HCl solution = 
Ionizable hydrogen ions in HCl = 
Molarity of NaOH solution = 
Volume of NaOH solution = 
Ionizable hydroxide ions in NaOH = 
(neutralization )
2.1 M is the molarity of the HCl solution.
From the reaction above, the rate is given by the following formula:
r = -(1/2) dA / dt = - dB / dt = (1/3) dC/ dt
Note that A and B charge is negative due to they decrease with time
given dA / dt = -0.110 M/s
hence dB / dt = -0.110 / 2 = -0.055 M/s
dC / dt = (-3/2) (-0.110) = 0.165 M/s
Answer:
Percentage yield = 0.49 × 10² %
Explanation:
Given data:
Actual yield of SO₂ = 4.309 ×10² g
Theoretical yield of SO₂ = 8.78 ×10² g
Percentage yield = ?
Solution:
Chemical equation:
2NiS₂ + 5O₂ → 2NiO + 4SO₂
Percentage yield:
Percentage yield = actual yield / theoretical yield × 100
Percentage yield = 4.309 ×10² g / 8.78 ×10² g × 100
Percentage yield = 0.491 × 100
Percentage yield = 49.1%
In scientific notation:
Percentage yield = 0.49 × 10² %
