Answer:
Xe:[Kr]4d¹⁰5(sp³d³)₆⁺² => Octahedral Geometry (AX₆)⁺²
Explanation:
Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆²
Ca. #Valence e⁻ = Xe + 6F - 2e⁻ = 1(8) + 6(7) - 2 = 48
Ca. #Substrate e⁻ = 6F = 6(8) = 48
#Nonbonded free pairs e⁻ = (V - S)/2 = (48 - 48)/2 = 0 free pairs
#Bonded pairs e⁻ = 6F substrates = 6 bonded pairs
BPr + NBPr = 6 + 0 = 6 e⁻ pairs => Geometry => [AX₆]⁺² => Octahedron
Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆⁺²
XeF₆⁺² => 6(sp³d³) hybrid orbitals => Octahedral Geometry (AX₆)
It is the attraction between two atoms resulting from a redistribution of their outer electrons. Atoms form chemical bonds in order to make their outer electron shells more stable. Some resist due to some being very big and electronegative
Answer:
D (Decomposition)
Explanation:
This reaction is a decomposition reaction because one substance (NaNO3) is being separated into two substances (NaNO2 and O2). Alternatively, you could use the process of elimination. The reaction can't be single/double replacement because there's only one reactant, it can't be synthesis because substances are being broken down, not formed, and it can't be combustion because O2 is a product, not a reactant, and CO2 and H2O aren't being produced, as is common with combustion reactions.
