Answer:
a )Li
b)O
c)F
Explanation:
a) Li-1s^2 2s^1
F-1s^2 2s^2 2p^5
it is easy to pull out e- from 2p orbit than 2s because 2s orbit is close to nucleus.Therefore Li have high ionisation enthalpy
b)oxygen ion is larger than Na because o have fewer proton
c)F because it requires only 1e to achieve stable noble gas configuration.Therefore to achieve stable nobke gas electonic configuration it accept 1e.
Answer:
1.552 moles
Explanation:
First, we'll begin by writing a balanced equation for the reaction showing how C8H18 is burn in air to produce CO2.
This is illustrated below:
2C8H18 + 25O2 -> 16CO2 + 18H2O
Next, let us calculate the number of mole of C8H18 present in 22.1g of C8H18. This is illustrated below:
Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol
Mass of C8H18 = 22.1g
Mole of C8H18 =..?
Number of mole = Mass /Molar Mass
Mole of C8H18 = 22.1/144
Mole of C8H18 = 0.194 mole
From the balanced equation above,
2 moles of C8H18 produced 16 moles of CO2.
Therefore, 0.194 mole of C8H18 will produce = (0.194x16)/2 = 1.552 moles of CO2.
Therefore, 1.552 moles of CO2 are emitted into the atmosphere when 22.1 g C8H18 is burned
Answer:
11%
Explanation:
1) Calculate van 't Hoff factor:
Δt = i Kf m
0.31 = i (1.86) (0.15)
i = 1.111
2) Calculate value for [H+]:
CCl3COOH ⇌ H+ + CCl3COO¯
total concentration of all ions in solution equals:
(1.11) (0.15) = 0.1665 m
This is a molality, but we will act as if it a molarity since we will assume the density of the solution is 1.00 g/cm3, which makes the molarity equal to the molality.
0.1665 = (0.15 − x) + x + x
x = 0.0165 M
3) Calculate the percent dissociation:
0.0165/ 0.15 = 11 %
Answer:
See explanation below
Explanation:
This reaction is known as the Grignard reaction. If's often used to add an alkyl to a molecule, in this case, a ketone. This also helps to reduce the carbonile to an alcohol.
The mechanism is taking place in 3 steps.
The first step involves the attack of the pair of electrons of the oxygen from the cyclohexanone to the MgBr, and the other pair takes the propyl.
The second step involves the breaking of this bond to have the OMgBr and the propyl attached to the carbon of the chain.
The last steps involves an hydration of the molecule, to turn the OMgBr into OH, and that would be the final product.
In this case, the final product will be 1-propyl-cyclohexanol.
The picture below, shows the mechanism and the drawing of the final product.
To find the molecular formula of the compound, we get the molar mass of empirical formula CH2o which is 30 g/mol. We divided the molecular mass of 90.087 g/mol by 30, we get 3. Hence, we multiply each element by 3, getting the molecular formula of C3H6O3.
