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babymother [125]
3 years ago
15

a mower uses 5/16 gallon of gas to mow the back yard. the side yard is only 2/3 the size of the backyard. How much gas will be n

eeded to mow the side yard?
Mathematics
1 answer:
Trava [24]3 years ago
3 0

Answer:

(5/24) gallons of gas to mow the side yard

Step-by-step explanation:

We can easily solve this proble by applying a rule of three

5/16 gallons of gas  ---------------------------------  for 1 backyard

x  gallons of gas ------------------------------------- 2/3 backyard

x = ((2/3)/1)*(5/16) gallons of gas

x = ((2/3))*(5/16) gallons of gas

x = ((10/48) gallons of gas

x = (5/24) gallons of gas

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2 years ago
Angles α and β are angles in standard position such that: α terminates in Quadrant I and sinα = 3/5 β terminates in Quadrant III
Arte-miy333 [17]

Answer:

-16/65

Step-by-step explanation:

Given sinα = 3/5 in quadrant 1;

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adj^2 = 5^2 = 3^2

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Since all the trig identity are positive in Quadrant 1, hence;

cosα = adj/hyp = 4/5

Similarly, if tanβ = 5/12 in Quadrant III,

According to trig identity

tan theta = opp/adj

opp = 5

adj = 12

hyp^2 = opp^2+adj^2

hyp^2 = 5^2+12^2

hyp^2 = 25+144

hyp^2 = 169

hyp = 13

Since only tan is positive in Quadrant III, then;

sinβ = -5/13

cosβ = -12/13

Get the required expression;

sin(α - β) = sinαcosβ - cosαsinβ

Substitute the given values

sin(α - β) = 3/5(-12/13) - 4/5(-5/13)

sin(α - β)= -36/65 + 20/65

sin(α - β) = -16/65

Hence the value of sin(α - β) is -16/65

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