F = ma.
Note Force should be = 150 N. Acceleration = 30 m/s2 ( Am presuming for your question you meant to write 30m/s2 and not 30m/s as you wrote)
150 = m ( 30)
150/30 = m.
5 = m
Mass of the object = 5 Kg.
it has a rocky core so the gravity from that compacts the gases extremly tight
Answer: Rubidium has 5 orbits/shells/energy levels.
Explanation: It's electron configuration is as follows: 2-8-18-8-1.
Answer:
n=6.56×10¹⁵Hz
Explanation:
Given Data
Mass=9.1×10⁻³¹ kg
Radius distance=5.3×10⁻¹¹m
Electric Force=8.2×10⁻⁸N
To find
Revolutions per second
Solution
Let F be the force of attraction
let n be the number of revolutions per sec made by the electron around the nucleus then the centripetal force is given by
F=mω²r......................where ω=2π n
F=m4π²n²r...............eq(i)
as the values given where
Mass=9.1×10⁻³¹ kg
Radius distance=5.3×10⁻¹¹m
Electric Force=8.2×10⁻⁸N
we have to find n from eq(i)
n²=F/(m4π²r)
