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jek_recluse [69]
3 years ago
14

The Robinson projection map is considered very useful because

Physics
1 answer:
Vladimir79 [104]3 years ago
7 0
Hello,
   The question states: <span>The Robinson projection map is considered very useful because...
The answer is \boxed{because \ most \ distances, \ sizes, \ and \ shapes \ are \ accurate.}

Hope this helped!

~FoodJunky
</span>
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If it takes 150 n of force to accelerate an object at 30 m/s what is the mass of the object
iris [78.8K]
F  =  ma.         

Note Force should  be = 150 N.  Acceleration = 30 m/s2   ( Am presuming for your question you meant to write 30m/s2  and not 30m/s as you wrote)

150 = m ( 30)

150/30  = m.

5 = m

Mass of the object = 5 Kg.
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Chloroplasts convert energy from the sun into ________________.Immersive Reader
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1) glucose

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Jupiter is denser than water, yet composed for the most part of two light gases, hydrogen and helium. What makes Jupiter as dens
Alex17521 [72]

it has a rocky core so the gravity from that compacts the gases extremly tight

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How many orbits/shells/energy levels does Rubidium have?
BabaBlast [244]

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2 years ago
In the Bohr model of the hydrogen atom, an electron({rm mass};m=9.1; times 10^{ - 31;}{rm kg}) orbits a proton at a distance of
max2010maxim [7]

Answer:

n=6.56×10¹⁵Hz

Explanation:

Given Data

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

To find

Revolutions per second

Solution

Let F be the force of attraction

let n  be the number of revolutions per sec made by the electron around the nucleus then the centripetal force is given by

F=mω²r......................where ω=2π  n

F=m4π²n²r...............eq(i)

as the values given where

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

we have to find n from eq(i)

n²=F/(m4π²r)

n^{2} =\frac{8.2*10^{-8} }{9.11*10^{-31}* 4\pi^{2} *5.3*10^{-11}  }\\ n^{2}=4.31*10^{31}\\ n=\sqrt{4.31*10^{31}}\\ n=6.56*10^{15}Hz

8 0
3 years ago
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