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Tamiku [17]
2 years ago
9

An object is moving with a force 30N then hits a wall to a stop in 0.5s.

Physics
1 answer:
devlian [24]2 years ago
6 0

The impulse and change in momentum of an object moving with a force 30N then hits a wall to a stop in 0.5s is 15Ns.

<h3>How to calculate impulse?</h3>

Impulse is the integral of force over time. It is calculated by multiplying the force applied by the time as follows:

∆p = Force × time

According to this question, an object is moving with a force 30N and then hits a wall to a stop in 0.5s.

Impulse = 30N × 0.5s = 15Ns

Therefore, the impulse and change in momentum of an object moving with a force 30N then hits a wall to a stop in 0.5s is 15Ns.

Learn more about impulse at: brainly.com/question/16980676

#SPJ1

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A 310-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,010 A. If the conductor is copper
Marizza181 [45]

Answer:

t = 166 years

Explanation:

In order to calculate the amount of years that electrons take to cross the complete transmission line. You first calculate the drift speed of the electrons by using the following formula:

v_d=\frac{I}{nqA}             (1)

I: current on the wire = 1,010A

n: free charge density = 8.50*10^28 electrons/m^3

A: cross-sectional area of the transmission line = π*r^2

r: radius of the cross-sectional area = 2.00cm = 0.02m

You replace the values of the parameters in the equation (1):

v_d=\frac{1,010A}{(8.50*10^{28}electron/m^3)(1.6*10^{-19}C)(\pi (0.02m)^2)}\\\\v_d=5.9*10^{-5}\frac{m}{s}

Next, you use the following formula:

t=\frac{x}{v_d}                     (2)

x: length of the line transmission = 310km = 310,000m

You replace the values of vd and x in the equation (2):

t=\frac{310,000m}{5.9*10^{-5}m/s}=5.24*10^9s

Finally, you convert the obtained t to seconds

t=5.24*10^9s*\frac{1\ year}{3.156*10^7s}=166.03\ years

The electrons take approximately 166 years to travel trough the complete transmission line

5 0
2 years ago
Have you ever visited an amusement park and taken a ride on a parachute drop ride? These types of rides take the passengers to a
Triss [41]

Answer & Explanation:

a)

Lenz's law states that the direction of induced electric current is always such that, it opposes the change in magnetic flux.

In a drop ride, the hub on which we sit and are hung to is an electromagnet and there are many such magnets mounted on the columns of the support. what happens is these electromagnets (in support) generate a repulsive magnetic field with respect to the field generated by the hub solenoids. this results in lift generation till the top of ride. reaching the top, the bar solenoids are at their maximum repulsive force. Then the solenoids in column are set current less means electric supply is cut off. this makes you fall under the effect of gravity. by the time you are half way down, column  solenoids are turned on again. As the hub solenoid approaches every single electromagnet in supporting columns. Due to change in magnetic field (with respect to lenz's law) an opposing current induces further providing resistance to the fall, this continues until the ride comes to rest completely. This is how it works.  

c) In addition, highly compressive springs, dampers, viscous dampers, etc. could be used in its place.

but the above listed cannot provide a differential braking,

have a limited lifecycle,

will provide resistance during lift also,

require higher maintenance

3 0
3 years ago
Car 1 drives 20 mph to the south, and car 2 drives 30 mph to the north. From the frame of reference of car 1, what is the veloci
EleoNora [17]
We subtract the velocity of car 1 from the velocity of car 2:
v=(30\ mph\ North)-(20\ mph\ South)
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4 0
2 years ago
Read 2 more answers
Tyson Gay's best time to run 100.0 meters was 9.69 seconds. What was his average speed during this run, in miles per hour? (3.28
FinnZ [79.3K]

Answer:

23.086 mile/h

Explanation:

Given,

Distance Tyson Gay run = 100 m

time of run, t = 9.69 s

average speed of the in mph = ?

Speed of the Gay = \dfrac{distance}{time}

v = \dfrac{100}{9.69}

     v = 10.32 m/s

1 m = 3.281 ft

10.32 m = 33.86 ft

1 mile = 5280 ft

1 ft = 1.8939 x 10⁻⁴ mile

33.86 ft/s = 6.413 x 10⁻³ miles/s

Speed of Tyson in mile/hr = 6.413 x 10⁻³ x 3600

                                           = 23.086 mile/h

Hence, speed of Tyson Gay's in mile/ hr is equal to 23.086 mph.

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2 years ago
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HELP
Free_Kalibri [48]

Answer:

Explanation:

Although there is absolutely NO regard for significant digits, I can help you with this, nonetheless.

The equation for Potential Energy is PE = mgh. We have everything but the height of the ball. We have to solve for that using a one-dimensional motion equation:

v² = v₀² + 2aΔx, where Δx is our displacement (the height we need for PE). Filling in and keeping in mind that at the max height of parabolic travel, the final velocity of the object is 0:

0 = (21.5)² + 2(-9.8)Δx and

0 = 462.25 - 19.6Δx and

-462.25 = -19.6Δx so

Δx = 23.58 m. Using this as the h in our PE equation:

PE = .19(9.8)(23.58) so

PE = 43.9 J, choice C.

8 0
3 years ago
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