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2 years ago

An object is moving with a force 30N then hits a wall to a stop in 0.5s.

1 answer:

6 0

The impulse and change in momentum of an object moving with a force 30N then hits a wall to a stop in 0.5s is 15Ns.

<h3>How to calculate impulse?</h3>

Impulse is the integral of force over time. It is calculated by multiplying the force applied by the time as follows:

∆p = Force × time

According to this question, an object is moving with a force 30N and then hits a wall to a stop in 0.5s.

Impulse = 30N × 0.5s = 15Ns

Therefore, the impulse and change in momentum of an object moving with a force 30N then hits a wall to a stop in 0.5s is 15Ns.

Learn more about impulse at: brainly.com/question/16980676

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Please Help

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The initial kinetic energy $KE_0$ is

$KE_0 = \frac{1}{2}mv_0^2 = \frac{1}{2}(400\:\text{kg})(10\:\text{m/s})^2$

$\:\:\:\:\:\;\:= 2×10^4\:\text{J} = 20\:\text{kJ}$

The final kinetic energy $KE$ is

$KE = \frac{1}{2}mv^2 = \frac{1}{2}(400\:\text{kg})(30\:\text{m/s})^2$

$\:\:\:\:\:\:\:= 1.8×10^5\:\text{J} = 180\:\text{kJ}$

The work done W on the car is

$W = \Delta{KE} = KE - KE_0$

$\:\:\:\:\:\:\:= 180\:\text{kJ} - 20\:\text{kJ} = 1.6×10^5\:\text{J}$

The power expended P is

$P = \dfrac{W}{t} = \dfrac{1.6×10^5\:\text{J}}{15\:\text{s}} = 10667\:\text{Watts}$

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Since the force he is applying is 5N and he carries it a distance of 10 meters and the displacement and the force are assumed to be in the same direction we have 5*10 <span>so 50 J </span>

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