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Tamiku [17]
2 years ago
9

An object is moving with a force 30N then hits a wall to a stop in 0.5s.

Physics
1 answer:
devlian [24]2 years ago
6 0

The impulse and change in momentum of an object moving with a force 30N then hits a wall to a stop in 0.5s is 15Ns.

<h3>How to calculate impulse?</h3>

Impulse is the integral of force over time. It is calculated by multiplying the force applied by the time as follows:

∆p = Force × time

According to this question, an object is moving with a force 30N and then hits a wall to a stop in 0.5s.

Impulse = 30N × 0.5s = 15Ns

Therefore, the impulse and change in momentum of an object moving with a force 30N then hits a wall to a stop in 0.5s is 15Ns.

Learn more about impulse at: brainly.com/question/16980676

#SPJ1

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5 0
3 years ago
What is the average speed of a car that travels 60 meters in 2<br> seconds?
blondinia [14]

Answer:

30 m/s

Explanation:

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6 0
3 years ago
What is the net force? <br><br> URGENT! thank you
alexandr402 [8]
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4 years ago
What is the maximum powr of a module in Watts to the nearest whole Watt?​
KonstantinChe [14]

Complete question is;

You are looking at a module specification

sheet that has the table of information

below. What is the maximum power of this

module in Watts to the nearest whole Watt?

Value

Polycrystalline si

Characteristic

Cell Type

Cell

Configuration

Voc

160 in series

137.2 V

V_imp: 29.3 V

Ilsc: 8.60 A

I_Imp: 8.02 A

Dimensions (mm/in): 1000 x 1600 x 50 mm / 39.4" x 63" x 2"

Weight: 10 kg / 22 lbs​

Answer:

P ≈ 235 Watts

Explanation:

Formula for power is;

P = IV

Now, for maximum power, we will make use of I_imp and V_imp given

Thus, P = I_imp × V_imp

We are given;

V_imp: 29.3 V

I_Imp: 8.02 A

Thus: P = 8.02 × 29.3 = 234.986 Watts

We are to approximate to the nearest whole watt.

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6 0
3 years ago
American eels (Anguilla rostrata) are freshwater fish with long, slender bodies that we can treat as uniform cylinders 1.0 m lon
algol [13]

Answer:

(c) 3 m/s;

Explanation:

Moment of inertia of the fish eels about its long body as axis

= 1/2 m R ² where m is mass of its body and R is radius of transverse cross section of body .

= 1/2 x m x (5 x 10⁻² )²

I  = 12.5 m x 10⁻⁴ kg m²

angular velocity of the eel

ω = 2 π n where n is revolution per second

=2 π n

= 2 π x 14

= 28π

Rotational kinetic energy

= 1/2 I ω²

= .5 x 12.5 m x 10⁻⁴  x(28π)²

= 4.8312m  J

To match this kinetic energy let eel requires to have linear velocity of V

1 / 2 m V² = 4.8312m

V = 3.10

or 3 m /s .

5 0
3 years ago
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