Question

A charge of 6.7 × 10^-15 coulombs is located at a point where its potential energy is 5.6 × 10^-12 joules. What is the electric potential at that point?
A. 2.3 × 10^2 volts
B. 4.7 × 10^2 volts
C. 8.4 × 10^2 volts
D. 9.2 × 10^2 volts

Answer 1

Answer

Option C - 8.4 × 10^2 volts

Explanation

Since, formula for electric potential is given by;

V= PE/ q

Here, V= electric potential

PE= potential energy

& q= charge

Given,

q= 6.7 × 10^-15 coulombs & PE= 5.6 × 10^-12 joules.

By putting the values of ‘q’ and ‘PE’ in the formula, we get:

V=  5.6 × 10^-12/ 6.7 × 10^-15

V= 8.35x10^2

V= 8.4x10^2 volts.

Therefore, the required electric potential of the charge is  8.4x10^2 volts.

Answer 2

Answer:

C. 8.4 × 10^2 volts

Explanation:

The potential energy of a charge is given by:

$U=qV$

where

q is the magnitude of the charge

V is the electric potential

In this problem, we have

$q=6.7\cdot 10^{-15} C$ is the charge

$U=5.6\cdot 10^{-12} J$ is the potential energy

Re-arranging the formula and using these numbers, we can find the electric potential:

$V=\frac{U}{q}=\frac{5.6\cdot 10^{-12} J}{6.7\cdot 10^{-15} C}=835.8 V = 8.4\cdot 10^2 V$