Answer:
No, it is not a function.
Step-by-step explanation:
If x+2 is a factor of x^3+6x^2+kx+10, then if we replace x by -2 in the polynomial x^3-6x^2+kx+10, we must get zero:
x=-2→(-2)^3-6(-2)^2+k(-2)+10=0→
-8-6(4)-2k+10=0→
-8-24-2k+10=0
-2k-22=0
Solving for k. Adding 22 both sides of the equation:
-2k-22+22=0+22
-2k=22
Dividing both sides of the equation by -2:
-2k/(-2)=22/(-2)
k=-11
Answer: k = - 11
Answer:
Step-by-step explanation:
The average rate of change is the slope. However, since this is not a linear function but an exponential one, we cannot determine the slope of the function, only the slope of the secant line that connects the x-values of 4 and 8. In order to do that we need to find the corresponding y-coordinate that goes with each of those x-values and plug them into the slope function. What we will get is a very loose interpretation of the rate of change of population, but that's all we have short of using calculus. It would be a closer estimation if we looked at x values of 4 and 5, or eve 4 ad 4.5. But that's not what we're being asked. So let's get to it.
Sub first 4 in for x and then 8, to get each y value:
to get that P(4) = 2742.16
to get that P(8) = 2937.29
The coordinates for these are (4, 2742.16) and (8, 2937.29)
Plug into the slope formula:
which gives you, in decimal form rounded to the nearest hundredth,
48.78 million.
The interpretation of this value in our situation is that between 1954 and 1958 the population increased 48.78 million people per year.
Answer:
the newer moat is 169 cm longer than the older one
Step-by-step explanation:
in order to find the difference in length of the two castles, we will first find the perimeters of the two castles then calculate the difference in the perimeters:
old castle:
dimension = 484cm by 386cm
perimeter = 484 + 386 = 870 cm
new castle:
dimension = 725cm by 314cm
perimeter = 725 + 314 = 1039 cm
difference = 1039 - 870 = 169 cm
The total length of the moats used is equals to the perimeter of the sand castles, therefore, the newer moat is 169 cm longer than the older one.