For ΔABC, ∠A = 8x - 10, ∠B = 10x - 40, and ∠C = 3x + 20. If ΔABC undergoes a dilation by a scale factor of 1 2 to create ΔA'B'C'
with ∠A' = 6x + 10, ∠B' = 70 - x, and ∠C' = 10x 2 , which confirms that ΔABC∼ΔA'B'C by the AA criterion? A) ∠A = ∠A' = 70° and ∠B = ∠B' = 60° B) ∠A = ∠A' = 35° and ∠B = ∠B' = 30° C) ∠B = ∠B' = 54° and ∠C = ∠C' = 40° D) ∠A = ∠A' = 76° and ∠C = ∠C' = 53°
1 answer:
If the triangles ABC and A'B'C' are similar, then
angle A = angle A'
8x-10 = 6x+10
8x-6x = 10+10
2x = 20
x = 20/2
x = 10
So angle A is
angle A = 8x-10
angle A = 8*10-10
angle A = 80-10
angle A = 70
making that the measure of angle A' as well
This is why the answer is choice A
You might be interested in
Answer:
x² + (y + 8)² = 81
Step-by-step explanation:
Centre (h,k) = (0,-8)
radius (r) = 9
(x - h)² + (y - k)² = r²
(x - 0)² + (y + 8)² = 9²
x² + (y + 8)² = 81
if we take £15837.77 to be the 100% and we increase it by 18.5%, that'll be 100% + 18.5% = 118.5%.
Answer:
hahahahahahahahahahahhahahahahahhahahahahahahahahhahahahahahahahahahahhahahahahahahahahhahahahahahahahahhahahwhwhwhwhwhwhahahahahhahahahhahahahahahahahahhahahahahahahahahahahahahahahhahahahahahahahahahahahahahhahahahahahahahahahahhahahahahahhahahahahahahahahahhahahahahahahahhahahahahahahahhahahahahahahahhahahahahhahahahahahah
<u>Answer-</u>
<u>Solution-</u>
The equation for time period of a simple pendulum is given by,
Where,
T = Time period,
L = Length of the rod,
g = Acceleration due to gravity.
Frequency (f) of the pendulum is the reciprocal of its period, i.e
Putting the values,
Answer:
and 5 what ?
Step-by-step explanation:
