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denis-greek [22]
4 years ago
12

Which is the correct way to represent 0.0035 kg by using scientific notation?

Chemistry
2 answers:
inn [45]4 years ago
8 0
That would be  3.5  ×  10⁻³ kg
lesya [120]4 years ago
7 0

Explanation:

A scientific notation is the notation in which a number is written in a decimal form and it is multiplied by 10 to the respective power.

For example, we have to write 0.0035 kg in scientific notation as 3.5 \times 10^{-3}.

Thus, we can conclude that the correct way to represent 0.0035 kg by using scientific notation is 3.5 \times 10^{-3}.

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What causes water to runoff
Nadusha1986 [10]

Answer:

C

Explanation:

Runoff occurs when there is more water than land can absorb so  it would be C.

8 0
3 years ago
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What rules should you follow when adding and subtracting ?
wariber [46]
Adding and subtracting with scientific notation may require more care, because the rule for adding and subtracting exponential expressions is that the expressions must havelike terms<span>. Remember that to be </span>like terms<span>, two expressions must have exactly the same base numbers to exactly the same powers. Thinking about decimal arithmetic, the requirement that we have the same powers makes sense, because that guarantees that all of the place values are lined up properly.</span>
5 0
4 years ago
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A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
a 6.7 volume of air, initially at 23 degrees celsius and .98 atm, is compressed to 2.7 L while heated to 125 degrees celsius. Wh
Annette [7]
Data:

V1 = 6.7 liter
T1 = 23° = 23 + 273.15 K = 300.15 K
P1 = 0.98 atm

V2 = 2.7 liter
T2 = 125° = 125 + 273.15 K = 398.15 K
P2 = ?

Formula:

Combined law of ideal gases: P1 V1 / T1 = P2 V2 / T2

=> P2 = P1 V1 T2 / (T1 V2)

P2 = 0.98 atm * 6.7 liter * 398.15 K / (300.15K * 2.7 liter)

P2 = 3.22 atm
6 0
4 years ago
When the concentration of reactant molecules is increased
a_sh-v [17]

Complete question is;

When the concentrations of reactant molecules are increased, the rate of reaction increases. The best explanation for this phenomenon is that as the reactant concentration increases,

A)the average kinetic energy of molecules increases.

B)the frequency of molecular collisions increases.

C)the rate constant increases.

D)the activation energy increases.

E)the order of reaction increases.

Answer:

B) The frequency of molecular collisions increases.

Explanation:

When we increase number of reactant molecules, the effective collision between the reactant molecules will form a product which also increases. As a result, the overall rate of the reaction will also increase which means the frequency of the molecular collision will also increase as well.

Thus, the correct answer is Option B

6 0
3 years ago
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