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Vinil7 [7]
3 years ago
6

PLEASE ANSWER QUICK ITS A TIMED QUIZ Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4

^x and y = 2^x−2 intersect are the solutions of the equation 4^x = 2^x−2. (4 points) Part B: Make tables to find the solution to 4^x = 2^x−2. Take the integer values of x between −3 and 3. (4 points) Part C: How can you solve the equation 4^x = 2^x−2 graphically? (2 poin
Mathematics
1 answer:
kramer3 years ago
6 0

A.  We have two lines:  y = 4-x   and   y = 8-x^-1

Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when

4-x = 8-x^-1

This is where the two lines will cross and that is the common point that satisfies both equations.

 

B.  4-x = 8-x^-1

 

 x         4-x      8-x^-1

______________

 

-3          7        8.33

-2          6        8.5

-1          5        9

 0          4        -

 1          3        7

 2          2        7.5

 3          1        7.67

 

The table shows that none of the x values from -3 to 3 is the solution because in no case does

4-x = 8-x^-1

 

To find the solution we need to rearrange the equation to find for x:

4-x = 8-x^-1

Multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

 

Therefore there are two points that satisfies the equation.

Find y:  

x=-4.236

y = 4-x  = 4 – (-4.236) = 8.236

y = 8-x^-1 =  8-(-4.236)^-1 = 8.236

 

x=0.236

 y = 4-x  = 4 – (0.236) = 3.764

y = 8-x^-1 =  8-(0.236)^-1 = 3.764

 

Thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

 

C.  To solve graphically the equation 4-x = 8-x^-1

We would graph both lines: y = 4-x  and   y = 8-x^-1

The point on the graph where the lines cross is the solution to the system of equations.

Just graph the points on part B on a Cartesian coordinate system and extend the two lines.  The solution is, as stated, the point where the two lines cross on the graph.

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San Francisco     4,200   7,200     12,000

Los Angeles       2,400    1,200      3,000

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San Francisco      400     4,800     3,000

Los Angeles      1,600     7,800     3,000

Step-by-step explanation:

a) Data and Calculations:

Stock on January 1: Matrix A

                              Hard    Soft       Plastic

San Francisco       1,000   3,000    6,000

Los Angeles         1,000   6,000    3,000

Sales in January: Matrix B

                             Hard    Soft       Plastic

San Francisco       700     1,200     2,000

Los Angeles         400       200        500

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San Francisco    600   1,500      1,500

Los Angeles      500     500        500

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Matrix B * 6 = Matrix B6

Sales in January: Matrix B

                             Hard    Soft       Plastic

San Francisco       700     1,200     2,000

Los Angeles         400       200        500

* 6

=

Sales from January to June: Matrix B6

                            Hard    Soft       Plastic

San Francisco     4,200   7,200     12,000

Los Angeles       2,400    1,200      3,000

Matrix C6 = Matrix C * 6

=

Restocking: Matrix C6

                          Hard     Soft       Plastic

San Francisco  3,600   9,000      9,000

Los Angeles    3,000   3,000      3,000

Inventory at the end of June =

Matrix A + Matrix C6 - Matrix B6

= Matrix D

Stock on January 1: Matrix A

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San Francisco       1,000   3,000    6,000

Los Angeles         1,000   6,000    3,000

+

Restocking: Matrix C6

                           Hard     Soft       Plastic

San Francisco  3,600   9,000      9,000

Los Angeles    3,000   3,000      3,000

-

Sales from January to June: Matrix B6

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San Francisco     4,200   7,200     12,000

Los Angeles       2,400    1,200      3,000

Ending Inventory: Matrix D:

                            Hard      Soft       Plastic

San Francisco      400     4,800     3,000

Los Angeles      1,600     7,800     3,000

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