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3 years ago

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Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speak

er, and one 12-Ω speaker so that the amplifier powers all speakers and their equivalent resistance when connected together in this way is 8 Ω? Compare the power output of your arrangement with the power output of a single 8-Ω speaker.

1 answer:

ANTONII [103]3 years ago

8 0

Answer:

(a) 8Ω (b) Ratio = Parra/P8 ohm = 1

Explanation:

Solution

Recall that,

An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

Now,

(a) How can two 8-Ω speakers be arranged, when one = 4-Ω speaker, and one =12-Ω speaker

The Upper arm is : 8 ohm, 8 ohm

The Lower arm is : 12 ohm, 4 ohm

The Requirement is = (16 x 16)/(16 + 16) = 8 ohm

(b) compare your arrangement power output of with the power output of a single 8-Ω speaker

The Ratio = Parra/P8 ohm = 1

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Explanation:

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Calculate the phase angle (in radians) for a circuit with a maximum voltage of 12 V and w-50 Hz. The voltage source is connected

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(c) is correct option.

Explanation:

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This is therefore the reason why volume was chosen as the most appropriate choice.

Read more about Volume here brainly.com/question/463363

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