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Marysya12 [62]
4 years ago
5

Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speak

er, and one 12-Ω speaker so that the amplifier powers all speakers and their equivalent resistance when connected together in this way is 8 Ω? Compare the power output of your arrangement with the power output of a single 8-Ω speaker.
Physics
1 answer:
ANTONII [103]4 years ago
8 0

Answer:

(a) 8Ω (b)  Ratio = Parra/P8 ohm = 1

Explanation:

Solution

Recall that,

An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

Now,

(a) How can  two 8-Ω speakers be  arranged, when one =  4-Ω speaker, and one =12-Ω speaker

The Upper arm is : 8 ohm, 8 ohm

The Lower arm is : 12 ohm, 4 ohm

The Requirement is  = (16 x 16)/(16 + 16) = 8 ohm

(b) compare  your arrangement  power output of with the power output of a single 8-Ω speaker

The Ratio = Parra/P8 ohm = 1

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Answer:

v₂ = 5.7 m/s

Explanation:

We will apply the law of conservation of momentum here:

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where,

Total Initial Momentum = 340 kg.m/s

m₁ = mass of bike

v₁ = final speed of bike = 0 m/s

m₂ = mass of Sheila = 60 kg

v₂ = final speed of Sheila = ?

Therefore,

340\ kg.m/s = m_{1}(0\ m/s) + (60\ kg)v_{2}\\v_{2} = \frac{340\ kg.m/s}{60\ kg}\\\\

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3 years ago
A 75 lb weight hangs from a string as shown in the figure. Find the tensions T1 and T2 in the string.
fomenos
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below is the solution:

<span>T2cos(30) - T1cos(50) = 0
</span><span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span><span>T2cos(30) - T1cos(50) = 0 --> T1 = T2cos(30)/cos(50)
</span>
<span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span>(<span>T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> Solve for T2

</span><span>T1 = -T1cos(50)i + T1sin(50)j
T2 = T2cos(30)i + T2sin(3)j
</span>
<span>(T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> T2[(cos(30)/cos(50))sin(50) + sin(30)] = 75*(grav) --> T2 = 75*grav/ [(cos(30)/cos(50))sin(50) + sin(30)]
</span>
<span> T2 = 1566.49 </span>
4 0
4 years ago
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5 0
3 years ago
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Answer:

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7 0
3 years ago
O
lbvjy [14]

Hi there!

1.

The period of a pendulum can be calculated using the following equation:
\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}

T = period (s)

L = length of string (m)
g = acceleration due to gravity (m/s²)

Plug in the values:

T = 2\pi \sqrt{\frac{4}{9.8}} = \boxed{4.014 s}

2.

Calculate the period:


T = \frac{\text{Time}}{\# of oscillations} = \frac{5}{20} = \boxed{0.4 s }

Frequency is the reciprocal of the period, so:


f = \frac{1}{T} = \frac{1}{0.4} = \boxed{2.5 Hz}

6 0
3 years ago
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