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3 years ago

Which is a disadvantage of using wind as an energy source?

Physics

2 answers:

Sholpan [36]3 years ago

6 0

C is the correct answer

lesantik [10]3 years ago

5 0

Answer:

it produces

Explanation:

a lot of waste

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Calculate the velocity of a car (in m/s) that starts from rest and accelerates at 5 m/s^2 for 6 seconds.

bagirrra123 [75]

Answer:

The final velocity of the car is 30 m/s.

Explanation:

Given that,

Initial speed of the car, u = 0

Acceleration of the car, $a=5\ m/s^2$

Time taken, t = 6 s

Let v is the final velocity of the car. It can be calculated using first equation of kinematics as :

$v=u+at$

$v=at$

$v=5\ m/s^2\times 6\ s$

v = 30 m/s

So, the final velocity of the car is 30 m/s. Hence, this is the required solution.

7 0

3 years ago

Choose the appropriate descriptor for the term square centimeter .

CaHeK987 [17]

Area because CM^2 is the unit used for Area

8 0

4 years ago

In a sea community near the floor of the ocean, a great white shark summons a goby fish to attach itself under its stomach. The

lubasha [3.4K]

Answer:

Commensalism

Explanation:

Commensalism is one example of the behavior of a goby and shark.

3 0

3 years ago

Read 2 more answers

A bowling ball with a circumference of 27 in. weighs 14.8 lb and has a radius of gyration of 3.43 in. If the ball is released wi

Marrrta [24]

Answer:

Distance covered is 37.63 ft

Solution:

As per the question:

Circumference of the bowling ball, C = 27 in

Weight of the bowling ball, w = 14.8 lb

Radius of gyration, k = 3.43 in

Velocity of release of the ball, v' = 23 ft/s = 276 in/s

Coefficient of friction, $\mu = 0.19$

Now,

We know that the circumference of the circle is given by:

C = $2\pi R$

27 = $2\pi R$

$R = \frac{27}{2\pi } = 4.29\ in$

Also, in case of rolling, we know that:

Angular velocity, $\omega = \frac{v}{R}$

$v = \omega R$

Now, applying the conservation of angular momentum along the floor:

Initial angular momentum = Final angular momentum

$m\omega' = m\omega + I\omega$

Moment of Inertia, I = $\frac{2}{5}mR^{2} = mk^{2}$

$mv'R = mvR + mk^{2}\times \frac{v}{R}$

$v'R = vR + k^{2}\times \frac{v}{R}$

$276\times 4.29 = 4.29v + 3.43^{2}\times \frac{276}{4.29}$

$1184.04 - 756.903 = 4.29v$

v = 99.56 in/s

Now,

Friction force, f = $\mu mg$

Also, acceleration of the ball can be computed as:

$\mu mg = - ma$

$a = - \mu g = - 0.19\times 386.09 = - 73.357\ in/s^{2}$

Now, the distance, d covered by the ball before rolling without slipping:

$v^{2} = v'^{2} + 2ad$

$99.56^{2} = 276^{2} + 2\times (- 73.357)d$

$99.56^{2} - 276^{2} = 2\times (- 73.357)d$

d = 451.65 in = 37.53 ft

7 0

3 years ago

An object will not lose its blank as it moves away from earths surface, but it will lose blank

ladessa [460]

Mass, weight. Mass is independent of the object’s location, whereas weight is not.

3 0

3 years ago