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bazaltina [42]
3 years ago
15

Particles in which state are close together, yet free to move around one another?

Physics
1 answer:
enyata [817]3 years ago
4 0
Particles in the liquid state of matter are close together, yet free to move around one another
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Which is the smallest unit of life?
emmasim [6.3K]

Answer:

the cell is the smallest unit

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Which state of matter would be described as a highly energized charge particles with moving extremely fast
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A distant large asteroid is detected that might pose a threat to Earth. If it were to continue moving in a straight line at cons
Vlada [557]

Answer:

The minimum speed required is 5.7395km/s.

Explanation:

To escape earth, the kinetic energy of the asteroid must be greater or equal to its gravitational potential energy:

K.E\geq P.E

or

\dfrac{1}{2}mv^2 \geq  G\dfrac{Mm}{R}

where m is the mass of the asteroid, R= 24,000,000\:m is its distance form earth's center, M = 5.9*10^{24}kg is the mass of the earth, and G = 6.7*10^{-11}m^3/kg\: s^2 is the gravitational constant.

Solving for v we get:

v \geq \sqrt{\dfrac{2GM}{R} }

putting in numerical values gives

v \geq \sqrt{\dfrac{2(6.7*10^{-11})(5.9*10^{24})}{(24,000,000)} }

\boxed{v\geq 5739.5m/s}

in kilometers this is

v\geq5.7395m/s.

Hence, the minimum speed required is 5.7395km/s.

5 0
3 years ago
A giant star has a luminosity of 300 its color is most likely to be
amm1812
<span>The correct answer is blue. If you look at a luminosity star chart, called the Hertzsprung Russell Diagram, you will see the measurement of luminosity on the left side, and you will see a curve of stars with different colors (which correlate to the colors of the stars). Look for 30 on the luminosity measurement (look between 1 and 100). Then, move horizontally across the diagram until you hit the stars, whose color will be blue. Thus, blue is the answer.</span>
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3 years ago
The chain of length L and mass per unit length rho is released from rest on the smooth horizontal surface with a negligibly smal
devlian [24]

Answer:

Part a)

a = \frac{x}{L} g

Part b)

T = \rho x g(1 - \frac{x}{L})

Part c)

v = \sqrt{gL}

Explanation:

Part a)

Net pulling force on the chain is due to weight of the part of the chain which is over hanging

So we know that mass of overhanging part of chain is given as

m = \rho x

now net pulling force on the chain is given as

F = \rho x g

now acceleration is given as

F = Ma

\rho x g = \rho L a

a = \frac{x}{L} g

Part b)

Tension force in the part of the chain is given as

mg - T = ma

\rho x g - T = \rho x a

\rho x(g - a) = T

\rho x (g - \frac{x}{L} g) = T

T = \rho x g(1 - \frac{x}{L})

Part c)

velocity of the last link of the chain is given as

a = \frac{x}{L} g

v\frac{dv}{dx} = \frac{x}{L} g

now integrate both sides

\int v dv = \frac{g}{L} \int x dx

\frac{v^2}{2} = \frac{gL}{2}

v = \sqrt{gL}

3 0
3 years ago
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