To solve this problem we will start from the given concept in which the number of turns is equivalent to the length of the thread per circumference of spool. That is:

$N = \frac{l}{\phi}$

Where,

l = length of the thread

$\phi$ = circumference of spool

For \phi we have that,

$\phi = 2\pi r \rightarrow 2\pi (0.01)$

For l we have that

l = 62.8m

Finally the number of Turns would be,

$N = \frac{l}{\phi}$

$N = \frac{62.8}{2\pi (0.01)}$

$N = 1000turns$

Therefore the number of turns of thread on the spool are 1000turns.

7 0

3 years ago

Some of the quantities you measure in this lab are vectors and some are scalers. When you add vectors together youneed to worry

GalinKa [24]

Answer:

B I think

Explanation:

4 0

3 years ago

A spider twirls a 25 mg fruit fly around in a circle with radius 17.6 cm at the end of a web. If the velocity of the fly is 110

olchik [2.2K]

Answer:

Fc = 1.7x10^-4 N

Explanation:

Convert everything to proper units:

m = 25mg = 2.5x10^-5 kg

r = 17.6cm = 0.176m

v = 110cm/s = 1.1m/s

the formula for centripetal force is Fc = mv^2 / r

Plug everything and solve for Fc;

fc = (2.5x10^-5)(1.1^2) / 0.176

Fc = 1.7x10^-4 N

8 0

3 years ago