<h3><u>Answer;</u></h3>
Ionic
Powdered sports drink is<u> ionic </u>
<h3><u>Explanation;</u></h3>
- <em><u>Sports drinks are beverages whose purpose is to help athletes replace water, electrolytes, and energy before and after training or competition.</u></em>
- Sport drinks contain may contain water, fuel and electrolytes which are used to regulate fluid balances in the body. Electrolytes are molecules that have electrical charge called ions, such as calcium , potassium, sodium and chloride ions.
- <em><u>Ionic compounds are made up of ions, that is positively charged ions and negatively charged ions which are joined together by ionic bonds. Electrolyte in sport drinks forms ionic bonds.</u></em>
Answer:
Explanation:
The equation of the reaction of Silver sulfide with aluminum in the presence of sodium bicarbonate (NaHCO₃)
3 Ag₂S(aq) + 2 Al(s) → 6 Ag (s) + Al₂S₃(aq)
Answer:
ΔS > 0 only for choice E: CH4(g) + H2O (g) → CO(g) + 3 H2(g)
Explanation:
Our strategy in this question is to use the trend in entropies :
S (solids) less than S (liquids) less than S (gases)
Also we have to look for the molar quanties involved of each state and their change to answer the question:
A. N2(g) + 3 H2(g) → 2 NH3(g)
Here we have 4 moles gases going to 2 moles of products, so the change in entropy is negative.
B. Na2CO3(s) + H2O(g) + CO2(g) → 2 NaHCO3(s)
The change in entropy is negative since we have 2 mol gases in the reactants and zero in the products.
C. CH3OH(l) → CH3OH(s)
A liquid has a higher entropy than a solid so ΔS is negative
D. False see A,B,C
E. The change in moles of gases is 4 - 2= 2, therefore ΔS is greater than O.
Answer:
3.1% is the fraction of the sample after 28650 years
Explanation:
The isotope decay follows the equation:
Ln[A] = -kt + Ln[A]₀
<em>Where [A] could be taken as fraction of isotope after time t, k is decay constant and [A]₀ is initial fraction of the isotope = 1</em>
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k could be obtained from Half-Life as follows:
K = Ln 2 / Half-life
K = ln 2 / 5730 years
K = 1.2097x10⁻⁴ years⁻¹
Replacing in isotope decay equation:
Ln[A] = -1.2097x10⁻⁴ years⁻¹*28650 years + Ln[1]
Ln[A] = -3.4657
[A] = 0.0313 =
<h3>3.1% is the fraction of the sample after 28650 years</h3>
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