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3 years ago

AgNO2+Na3PO4 Solve and predict if its a precipitate

1 answer:

4 0

To identify a precipitation reaction and predict solubilities. ... solution of potassium dichromate to give a reddish precipitate of ... When aqueous solutions of silver nitrate and potassium dichromate are ...
Missing: AgNO2+

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Calculate the average rate of decomposition of NH4NO2 by the reaction 2NH4O5(aq) --> N2(g) H2O(g) at the following time inter

igor_vitrenko [27]

Answer:

$r=-0.033\frac{M}{s}$

Explanation:

Hello!

In this case, since the average rate of reaction is computed as a change given by:

$r=\frac{\Delta [NH_4NO_2 ]}{\Delta t}$

In such a way, given the concentrations at the specified times, we plug them in to obtain:

$r=\frac{(1.48M-4.12M)}{(330s-250s)}\\\\r=-0.033\frac{M}{s}$

Whose negative sign means the concentration decreased due to the decomposition.

Best regards!

6 0

2 years ago

Where is earths mantle located

matrenka [14]

<span>it is located directly under the sima</span>

4 0

3 years ago

Read 2 more answers

For the following exothermic reaction, A+B⇌C+D + Heat, if the temperature is increased, the reaction will experience a shift to

Elodia [21]

(Left) I’m pretty sure

6 0

3 years ago

The expected value for a chemical equation is 47g of water, after an experiment you find that you have 2.58 moles of water. What

strojnjashka [21]

<h3><u>Answer</u>;</h3>

Actual yield = 46.44 g

<h3><u>Explanation;</u></h3>

1 mole of water = 18 g/mol

Therefore;

The experimental yield = 2.58 moles

equivalent to ; 2.58 × 18 = 46.44 g

The theoretical value is 47 g

Percentage yield = 46.44/47 × 100%

= 98.8%

The questions asks for actual yield = 46.44 g

6 0

3 years ago

Extend your thinking: The slow decay of radioactive materials can be used to find the age of rocks, fossils, and archaeological

lisov135 [29]

The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

<h3>What is the half-life of a radioactive material?</h3>

The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.

The half-life, $t_\frac{1}{2}$ , the age, t, and amount remaining, $A_{r}$ , of a radioactive material are related by the formula below:

$t = \frac{t_\frac{1}{2}*A_{r}}{-ln2}$

Half-life of carbon-14 = 6000 years

For the Egyptian papyrus with 63% of its original carbon-14 atoms: $t = \frac{6000*0.63}{-0.63} = 4000\:years$

For the Aboriginal charcoal with 22% of its original carbon-14 atoms:

$t = \frac{6000*0.22}{-0.63} = 13106.5\:years$

For the Mayan headdress with 79% of its original carbon-14 atoms:

$t = \frac{6000*0.79}{-0.63} = 2040\:years$

Neanderthal skull with 3% of its original carbon-14 atoms:

$t = \frac{6000*0.03}{-0.63} = 30353\:years$

Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

Learn more about half-life at: brainly.com/question/26689704

#SPJ1

6 0

1 year ago