Answer:
The velocity of the first block is 1.15m/s while of the second block 2.56m/s.
Explanation:
Momentum is only conserved in an isolated system, and because this problem requires us to find the value of the two variables, we need two equations; therefore, to conserved momentum the energy must be released in to the system only after the collision has occurred.
Therefore, from conservation of momentum
and from conservation of energy
Thus, we have two equations and two unknowns
which has solutions
and
Since the blocks cannot pass through each other, the 0.5kg block cannot have (moves to the left) while the 0.4 kg block has (moves to the right); therefore, we take the first solution for the velocities:
.
Thus , the velocity of the first block is 1.15m/s while of the second block 2.56m/s.
Gravity i think but if uts not gravity then it will be air resistance
Explanation:
The static pressure is P = ρgh, where ρ is the density of the fluid and h is the depth.
For the first person:
P = (1000 kg/m³) (9.8 m/s²) (2.3 m)
P = 22,500 Pa
For the second person:
P = (1000 kg/m³) (9.8 m/s²) (3 m)
P = 29,400 Pa
Answer:
Electric charge in the earth will be
Explanation:
We have given that E = 116 N/C
Radius of the earth R = 6371 km = 6371000 m
We have to find the electric charge in the earth '
We know that electric field due to charge is given by . here K is coulomb's constant
So
So electric charge in the earth will be
Answer:
Assume two identical cans filled with two types of soup having same mass are rolling down on an inclined plane in same conditions. In terms of inertia different types of soup will indicate different viscosity. The higher viscosity fillings indicates more part of the soup mass is rotating together with the can’s body. This means that for the can with lower viscosity soup has a lower moment of inertia and the can with higher viscosity has higher moment of inertia while the same gravity makes them to roll.
incline angle = θ ; can's mass = m ; Radius of the can's = R , Angular acceleration for Can 1 = α1 ; Angular acceleration for Can 2 = α2
T1 = Inertia of Can with high viscosity soup
T2 = Inertia of Can with low viscosity soup
M1 rolling moment of Can 1
M2 rolling moment of Can 2
equation is given by
T1*α1 = M1 - (a)
T2*α2 = M2 - (b)
M1 = M2 = m*g*R*sin(θ). (c)
as assumed T1 > T2
from the three equation (a), (b) & (c)
the α2 > α1
Angular acceleration of Can 2 is higher than Can 1. Already stated that Can 1 has more viscous soup as compared to Can 2.